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olga2289 [7]
2 years ago
11

I don't get it ???:/

Mathematics
2 answers:
shutvik [7]2 years ago
8 0

Answer:

There's no mode

Step-by-step explanation:

The answer is the number that occurs more often for example: (6, 3,9,6,6,5,9,3) 6 occurs more often so that's the mode

jeka57 [31]2 years ago
5 0
No mode also have a great day please
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Answer true or false for 1-10 (picture above)
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3 0
3 years ago
40 pecks 6 quarts − 20 pecks 7 quarts
OLEGan [10]
4 pecks is the answer
6 0
3 years ago
Read 2 more answers
Is y = |x| a function
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Yes

Step-by-step explanation:

A function is a relation for which each value from the set of the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.

Hope this helps!

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3 years ago
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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
2 years ago
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