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olga55 [171]
3 years ago
7

Can someone please put these in order from least to greatest? Thanks

Mathematics
1 answer:
Virty [35]3 years ago
3 0

Answer:

Luna wanna play among us with me (sorry I’m bored) the code is: PXQMKF

Step-by-step explanation:

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1. = 5 animals

2. = 22 animals

3. = 32 animals

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Paul rolls a fair dice 174 times.<br> How many times would Paul expect to roll an odd number?
nekit [7.7K]

Answer:

87 times as the dice has 3even numbers and 3 odd numbers so chance is 50% so half of 174 is 87.....times

Step-by-step explanation: hope this helps

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Abox is 30 inches long wide, 16 inches long, and 14 inches high. To the nearest cubic inch,
Scorpion4ik [409]

Answer:

6720in^{3}

Step-by-step explanation:

length x width x height

30 in x 16 in x 14 in = 6720in^{3}

6 0
3 years ago
Which statement identifies how to show that j(x) = 11.6ex and k(x) = In (StartFraction x Over 11.6 EndFraction) are inverse func
Vadim26 [7]

Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

For j(k(x));

j(k(x)) = j[(ln x/11.6)]

j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}

j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)

j[(ln x/11.6)] = 11.6 * x/11.6

j[(ln x/11.6)] = x

Hence j[k(x)] = x

Similarly for k[j(x)];

k[j(x)] = k[11.6e^x]

k[11.6e^x] = ln (11.6e^x/11.6)

k[11.6e^x]  = ln(e^x)

exponential function will cancel out the natural logarithm leaving x

k[11.6e^x]  = x

Hence k[j(x)] = x

From the calculations above, it can be seen that j[k(x)] =  k[j(x)]  = x, this shows that the functions j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6} are inverse functions.

4 0
3 years ago
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