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In-s [12.5K]
4 years ago
6

Energy

Physics
2 answers:
Ahat [919]4 years ago
7 0
I think the answer may be D- mechanical
Setler79 [48]4 years ago
3 0
The answer is OD) Mechanical
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A 39.5 kg child stands at the center of a 125 kg playground merry-go-round which rotates at 3.10 rad/s. If the child moves to th
Neporo4naja [7]
Using the law of conservation of angular momentum, we have 

<span>I1 w1 = I2 w2 </span>

<span>ie., m1r^2/2 x w1 = ( m1r^2/2 + m2r^2 ) w2 </span>

<span>ie., new angular velocity w2 = m1 w1 / ( m1+ 2m2) = 125 x 3.1 / ( 125 + 2 x39.5 ) </span>

<span>= 1.8995 = 1.9 rad /sec ( nearly )</span>
3 0
4 years ago
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
Darina [25.2K]

Answer:

<em>a. t = 2.02 s </em>

<em>b. d = 20.2 m</em>

Explanation:

<u>Horizontal Motion </u>

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

\displaystyle t=\sqrt{\frac{2h}{g}}

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

\displaystyle d=v.t

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

b.

The range is:

\displaystyle d=10\cdot 2.02

d = 20.2 m

7 0
3 years ago
Without inertia, how would an object that is experiencing a centripetal force behave?
nikitadnepr [17]
The correct option is this: IT WOULD MOVE IN A CURVED CIRCULAR PATH.
Objects that are travelling in circular paths change directions all the time as they move round the circle, but they are prevented from moving off in a straight line by centripetal force. The centripetal force keeps pulling the objects towards the center of the circle. <span />
8 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 80m. The time, in seconds, it takes to reach the ground is:__________.
Aleonysh [2.5K]

Answer:

4.04 s

Explanation:

h = vi + 1/2 a t ^2

HERE  h = 80 m , vi = 0 , a =9.81 m/s^2

80 = 0 + 1/2 × 9.81 × t ^2

80 = 4.905 t^2

t^2 = 80/4.905

t ^2 = 16.30988

t = square root of 16.30988

t =  4.0385 s

t = 4.04 s

4 0
3 years ago
A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electr
NISA [10]

Answer:

The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

Explanation:

Given that,

Radius of solid sphere = R

Charge = q

According to figure,

Suppose r is the distance between the point P and center of sphere.

If \rho be the volume charge density,

Then, the charge will be,

q=\rho\times\dfrac{4}{3}\pi R^3.....(I)

Consider a Gaussian surface of radius r.

We need to calculate the electric field outside the sphere

Using formula of electric field

\oint{\vec{E}\cdot \vec{dA}}=\dfrac{Q}{\epsilon_{0}}

E\times4\pi r^2=\dfrac{\rho\dotc \dfrac{4}{3}\pi r^3}{\epsilon_{0}}

Put the value from equation (I)

E\times4\pi r^2=\dfrac{qr^3}{\epsilon_{0}R^3}

E=\dfrac{qr}{4\pi\epsilon_{0}R^3}

Hence, The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

4 0
3 years ago
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