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Alexandra [31]
3 years ago
11

What is the kinetic energy of a 9.0 kg steelhead if its speed is 16 m/s?

Physics
1 answer:
Vesnalui [34]3 years ago
8 0

<u>We are given:</u>

Mass of the Steelhead(m) = 9 kg

Velocity of the Steelhead(v) = 16 m/s

<u>Calculating the Kinetic Energy:</u>

KE = 1/2mv²

replacing the variables

KE = 1/2 * 9 * (16)²

KE = 1152 Joules

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A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is t
Snezhnost [94]

Answer:

Impulse of force = -80 Ns

Explanation:

<u>Given the following data;</u>

Mass = 50kg

Initial velocity = 1.6m/s

Since she glides to a stop, her final velocity equals to zero (0).

Now, we would find the change in velocity.

Change \; in \; velocity = final \; velocity - initial \; velocity

Substituting into the equation above;

Change in velocity = 0 - 1.6 = 1.6m/s

Impulse \; of \; force = mass * change \; in \; velocity

Substituting into the equation, we have;

Impulse \; of \; force = 50 * -1.6

<em>Impulse of force = -80 Ns</em>

<em>Therefore, the impulse of the force that stops her is -80 Newton-seconds and it has a negative value because it is working in an opposite direction, thus, bringing her to a stop. </em>

5 0
2 years ago
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Hitman42 [59]

Answer:

the balls reached a height of 4.9985 m

Explanation:

Given the data in the question;

mass one m = 3.8 kg

mass two M = 2.1 kg

Initial velocities

u = 22 m/s

U = { moving downward} = 12 m/s

Now, using the law conservation of linear moment;

mu + MU = v( m + M )

we solve for "v" which is the velocity of the ball s after collision;

v = (mu + MU) / ( m + M )

so we substitute our given values into the equation

v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )

v = ( 83.6 - 25.2 ) / 5.9

v = 58.4 / 5.9

v = 9.898 m/s

Now, we determine required height using the following relation;

v"² - v² = 2gh

where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²

0 - v² = 2gh

v² = -2gh

so we substitute

( 9.898 )² = -2 × -9.8  × h

97.97 = 19.6 × h

h = 97.97 / 19.6

h = 4.9985 m

Therefore, the balls reached a height of 4.9985 m

8 0
3 years ago
Enumerate two ways that you practice to control manage noise pollution
motikmotik
1. Sound insulation at construction sides.
2. Using silencers in automobiles and replacing old noisy machines with new quitter machines or using lubricants
4 0
2 years ago
A car accelerates from rest to a speed 20 m/s in 12 s. Find the distance the car travels this time
Andrew [12]
The first thing we need to do is figure out what equation to use. We will use the following kinematic equation...

Δx = (final velocity + initial velocity) x time / 2

We know that the car accelerates from rest, so initial velocity = 0 m/s
We also know final velocity = 20 m/s and time = 12s

Now we just need to plug everything in.

Δx = (20 x 12)/2 = 120 meters
6 0
3 years ago
Question 26 suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of
ololo11 [35]

<span>The answer is 6 kg the mass of the second object. By using Inversely proportional formula it means that (14 kg) (3 m/s</span>²<span>) = M (7 m/s</span>²<span>). Where M is the mass of the second object. For the Newton’s second law of motion formula which is: Force = mass x acceleration, we have:</span>

<span>F = (14 kg) (3 m/s</span>²<span>) = 42 N</span>

 

Therefore:

<span>42 N = M (7 m/s</span>²)

<span>M = (42 N) / (7 m/s</span>²<span>)</span>

M = 6 kg mass of the second object

4 0
3 years ago
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