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Alexandra [31]
2 years ago
11

What is the kinetic energy of a 9.0 kg steelhead if its speed is 16 m/s?

Physics
1 answer:
Vesnalui [34]2 years ago
8 0

<u>We are given:</u>

Mass of the Steelhead(m) = 9 kg

Velocity of the Steelhead(v) = 16 m/s

<u>Calculating the Kinetic Energy:</u>

KE = 1/2mv²

replacing the variables

KE = 1/2 * 9 * (16)²

KE = 1152 Joules

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Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

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Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

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2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

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suppose a car manufacturer tested its cars for front end collsion by hauling them up on a crane and dropping them from a certain
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Initial height: 66.5 m

Explanation:

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If we neglect air resistance, the total mechanical energy of the car is conserved during the fall, therefore we can write:

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where :

K_i = 0 is the kinetic energy of the car at the top (it starts from rest)

U_i = mgh is the gravitational potential energy of the car at the top, with:

m = the mass of the car

g = the acceleration of gravity

h = the heigth of the car

K_f = \frac{1}{2}mv^2 is the kinetic energy of the car just before hitting the ground, with

v = 130 km/h final speed of the car

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Re-arranging the equation,  we find

mgh=\frac{1}{2}mv^2

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g=9.8 m/s^2\\v = 130 km/h = 36.1 m/s

Solving for h, we find the initial height of the car:

h=\frac{v^2}{2g}=\frac{36.1^2}{2(9.8)}=66.5 m

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647  

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