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Alexandra [31]
3 years ago
11

What is the kinetic energy of a 9.0 kg steelhead if its speed is 16 m/s?

Physics
1 answer:
Vesnalui [34]3 years ago
8 0

<u>We are given:</u>

Mass of the Steelhead(m) = 9 kg

Velocity of the Steelhead(v) = 16 m/s

<u>Calculating the Kinetic Energy:</u>

KE = 1/2mv²

replacing the variables

KE = 1/2 * 9 * (16)²

KE = 1152 Joules

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In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (Fo
Eddi Din [679]

Answer:

Among those two medium, light would travel faster in the one with a reflection angle of 32^{\circ} (when light enters from the air.)

Explanation:

Let v_{1} denote the speed of light in the first medium. Let v_{\text{air}} denote the speed of light in the air. Assume that the light entered the boundary at an angle of \theta_{1} to the normal and exited with an angle of \theta_{\text{air}}. By Snell's Law, the sine of \theta_{1}\! and \theta_{\text{air}}\! would be proportional to the speed of light in the corresponding medium. In other words:

\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}.

When light enters a boundary at the critical angle \theta_{c}, total internal reflection would happen. It would appear as if the angle of refraction is now 90^{\circ}. (in this case, \theta_{\text{air}} = 90^{\circ}.)

Substitute this value into the Snell's Law equation:

\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}.

Rearrange to obtain an expression for the speed of light in the first medium:

v_{1} = v_{\text{air}} \cdot \sin(\theta_{1}).

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For 0 < \theta < 90^{\circ}, \sin(\theta) is monotonically increasing with respect to \theta. In other words, for \!\theta in that range, the value of \sin(\theta)\! increases as the value of \theta\! increases.

Therefore, compared to the medium in this question with \theta_{c} = 27^{\circ}, the medium with the larger critical angle \theta_{c} = 32^{\circ} would have a larger \sin(\theta_{c}). such that light would travel faster in that medium.

4 0
3 years ago
What is a current potential difference graphs?
alexandr402 [8]

Answer:

Explanation:

Voltage and current in resistors

A graph of current against potential difference shows you how the current flowing through a component varies with the potential difference across it. The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it.

5 0
4 years ago
Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak
Mashutka [201]

Answer:

Part a)

\Delta \phi = 2.2 \pi

Part b)

f = 411.3 Hz

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

\Delta x = 3\sqrt2 - 3

\Delta x = 1.24 m

now phase difference is related with path difference as

\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)

\Delta \phi = \frac{2\pi}{\lambda}(1.24)

here in order to find the wavelength

\lambda = \frac{c}{f}

\lambda = \frac{340}{300} = 1.13

now we have

\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi

Part b)

Now we know that when phase difference is odd multiple of \pi

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

\Delta \phi = 3\pi

so we have

3\pi = \frac{2\pi}{\lambda}(1.24)

so we have

\lambda = 0.827

now we have

\frac{340}{f} = 0.827

f = 411.3 Hz

4 0
3 years ago
A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on Mars?
zhannawk [14.2K]
Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg
8 0
3 years ago
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What is the acceleration of a 25 kg object when a 200 N force is applied to it?​
Sav [38]

Answer: 8

Explanation: 200/25=8

5 0
3 years ago
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