The magnitude of the vector B is 10.9
A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.
To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.
Vector B has components,
x = 2.4
y = 9.8
z = 4.1
Applying the formula,
|B| = √x²+y²+z²
|B| = √(2.4)² + (9.8)² + (4.1)²
|B| = √5.76+96.04+16.81
|B| = √118.61
|B| = 10.9
Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)
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The ozone layer traps heat from the sun's heat. only three-fourths are reflected back out into space by the ozone layer. the greenhouse effect traps carbon dioxide and so does the ozone layer.
Answer:
and 
. The missing ion would be 
.
Explanation:
In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.
In this question, the two ionic compounds are:
, and
.
In particular,
- is made up of
ions and 
ions, while - is made up of
ions and ions.
In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)
- is a cation. In , was bounded anions. During the reaction, it bonds with anions to produce .
- is also a cation. In , was bounded to ions. During the reaction, it bonds with anions to produce .
Hence, the two products will be and .
Note that charges on the ions must balance. For example, a ion carries twice as much charge as an ion. As a result, each ion would bond with twice as many ions as would in .
Answer:
3 mA.
Explanation:
The following data were obtained from the question:
Resistor (R) = 500 Ω
Potential difference (V) = 1.5 V
Current (I) =.?
Using the ohm's law equation, we can obtain the current as follow:
V = IR
1.5 = I x 500
Divide both side by 500
I = 1.5 / 500
I = 3×10¯³ A.
Therefore, the current in the circuit is 3×10¯³ A.
Finally, we shall convert 3×10¯³ A to milliampere (mA).
This can be obtained as follow:
Recall:
1 A = 1000 mA
Therefore,
3×10¯³ A = 3×10¯³ × 1000 = 3 mA
Therefore, 3×10¯³ A is equivalent to 3 mA.
Thus, the current in mA flowing through the circuit is 3 mA.
