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Viefleur [7K]
2 years ago
14

Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h

er? Why or why not?
Physics
2 answers:
likoan [24]2 years ago
6 0

Answer:

I disagree with her because many substances show fluorescence under ultraviolet light, not microwaves.

Explanation:

kompoz [17]2 years ago
4 0

Answer:

In disagreement

Explanation:

Fluorescence can be defined as the phenomenon by which an object emits visible light when placed in front of ultraviolet light. In fluorescence, the absorbed light increases the energy band of the electrons, causing them to go into a more excited state. The electrons, before they release the absorbed energy in the form of light, lose a part of the energy due to the vibration of the molecules. When they return to their initial state, the electrons will emit light.

While microwaves are electromagnetic waves whose frequency is high, and are used for the transmission of high-speed telegraphic signals and for the communication of satellites and do not emit light.

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A projectile fired up into the air at an angle has a range of 235 m and a flight time of 47 s.
madam [21]
<h2>Answer:5ms^{-1},133.6m,51.18ms^{-1}</h2>

Explanation:

Let v_{x},v_{y} be the horizontal and vertical components of velocity.

Question a:

Horizontal component of velocity is the ratio of range and time of flight.

So,horizontal component of velocity is \frac{235}{47}=5ms^{-1}

So,v_{x}=5ms^{-1}

Question b:

Time of flight=\frac{2v_{y}}{g}

So,v_{y}=\frac{47\times 9.8}{2}=51.18ms^{-1}

Maximum height is given by \frac{v_{y}^{2}}{2g}

So,maximum height is \frac{51.18^{2}}{2\times 9.8}=133.6m

Question c:

The vertical velocity is already calculated in Question b.

v_{y}=51.18ms^{-1}

7 0
2 years ago
Which of the following equations describes photosynthesis?​
BigorU [14]

Answer:

The chemical equation for photosynthesis is 6CO2+6H2O→C6H12O6+6O2.

Explanation:

4 0
2 years ago
Which excited electron has the lowest energy?
bearhunter [10]

Answer:

The lowest energy of electron is the ground state.

Explanation:

4 0
2 years ago
Read 2 more answers
A 48.0-kg skater is standing at rest in front of a wall. By pushing against the wall she propels herself backward with a velocit
Kipish [7]

Answer:

F = 47.6 N

Explanation:

  • Newton's 2nd law can be expressed as the rate of change of the total momentum, respect of time, as follows:

       F = \frac{\Delta p}{\Delta t}

  • So, in order to find the average force exerted by the skater on the wall, we can find the change in momentum due to the force exerted by the wall (which is equal and opposite to the one exerted by the skater), and  divide it by the time interval , as follows:

       F_{wall} = \frac{\Delta p}{\Delta t} =\frac{(48.0 kg*(-1.06m/s)}{1.07s} = -47.6 N

       ⇒ Fsk = 47.6 N (normal to the wall)

3 0
3 years ago
A vertical spring has a spring constant of 2900 N/m. The spring is compressed 80 cm and a 8 kg spider is placed on the spring. T
Serga [27]

Answer:

a)  k_{e} = 928 J , b)U = -62.7 J , c) K = 0 , d) Y = 11.0367 m,  e)  v = 15.23 m / s  

Explanation:

To solve this exercise we will use the concepts of mechanical energy.

a) The elastic potential energy is

      k_{e} = ½ k x²

      k_{e} = ½ 2900 0.80²

      k_{e} = 928 J

b) place the origin at the point of the uncompressed spring, the spider's potential energy

     U = m h and

     U = 8 9.8 (-0.80)

     U = -62.7 J

c) Before releasing the spring the spider is still, so its true speed and therefore the kinetic energy also

      K = ½ m v²

      K = 0

d) write the energy at two points, maximum compression and maximum height

     Em₀ = ke = ½ m x²

     E_{mf} = mg y

     Emo = E_{mf}

     ½ k x² = m g y

     y = ½ k x² / m g

     y = ½ 2900 0.8² / (8 9.8)

     y = 11.8367 m

As zero was placed for the spring without stretching the height from that reference is

     Y = y- 0.80

     Y = 11.8367 -0.80

     Y = 11.0367 m

Bonus

Energy for maximum compression and uncompressed spring

     Emo = ½ k x² = 928 J

     E_{mf}= ½ m v²

     Emo = E_{mf}

     Emo = ½ m v²

      v =√ 2Emo / m

     v = √ (2 928/8)

     v = 15.23 m / s

8 0
3 years ago
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