Answer:
SI unit: kg/m³
but g/cm³ is commonly used
Explanation:
Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.
To determine the number of moles of air present in the tank, we assume that air is an ideal gas in order for us to use the following equation,
n = PV/RT
Substituting the known values,
n = (195 atm)(350 L) / (0.0821 L.atm/mol.K)(10 + 273.15 K)
n = 2935.91 moles
Thus, the number of moles of air is approximately 2935.91 moles.
Hello I took this test just now and got 100% your correct answer would be C. Hope this helps.
