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3 years ago

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Cabbage juice turns pink in solutions with pH below 7 and green in solutions with pH above 7. You drop some cabbage juice in a s

ink full of soapy dishes and in a glass of soda. The cabbage juice is green in the soapy water and pink in the soda. Which substance is basic?

1 answer:

Ann [662]3 years ago

8 0

<span>Basic substances, when dissolved in water, give pH above 7</span>

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If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid

Anvisha [2.4K]

The complete question is

If the compound below is oxidized, the resulting product is ___.

the compound given is Butanal

Select one:

a. methane and propane

b. butanal

c. butanoic acid

d. butane

Answer:

C. Butanoic Acid

Explanation:

When Butanal is oxidized using reagents like KMnO4, Tollens reagent etc.

When Aldehyde is oxidized corresponding Carboxylic Acid is produced

Butanal → Butanoic Acid

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3 years ago

Can anyone please help me

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Q1. Chemical, Physical, Physical, Physical
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3 years ago

What is the electron configuration of an electrically neutral alkaline earth metal? please explain

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Answer:

The elements in Group 2 (beryllium, magnesium, calcium, strontium, barium, and radium) are called the alkaline earth metals (see Figure below). These elements have two valence electrons, both of which reside in the outermost s sublevel. The general electron configuration of all alkaline earth metals is ns

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3 years ago

Crime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the

almond37 [142]

The powder could be acetaminophen, analgesic having chemical formula $C_{17}H_{21}NO_{4}$

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = $\frac{mass}{molar \;mass}$

Moles of carbon = $\frac{67.31g}{12g/mole}$

=5.60 moles

Moles of hydrogen = $\frac{mass}{molar \;mass}$

Moles of hydrogen = $\frac{6.978 g}{1 g/mole}$

=6.978 moles

Moles of nitrogen = $\frac{mass}{molar \;mass}$

Moles of nitrogen = $\frac{4.617 g}{14 g/mole}$

=0.329 moles

Moles of oxygen = $\frac{mass}{molar \;mass}$

Moles of oxygen = $\frac{21.10 g}{16 g/mole}$

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is $C_{17}H_{21}NO_{4}$ .

Learn more about the empirical formula here:

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Which stage of the cell cycle usually lasts the longest

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The interphase usually lasts the longest

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