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tatiyna
3 years ago
9

A rectangular metal block measures 10cm x4 cm x 5cm. Given that the density of the

Physics
1 answer:
kap26 [50]3 years ago
4 0

10cm=14cm which well give you something idont know lol

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Plz helpppp............​
horsena [70]

Explanation:

anyone use zoom

code:- 2574030731

pass:- HELLO

Z●●M

7 0
3 years ago
A 1.00 x 104 W electric motor is used to lift a
Alexus [3.1K]

Answer: 52%

Explanation:

1W = 1 J/s

motor input is 10000 J/s

Potential energy change

PE = 955(9.81)(25.0) = 234,213.75

power needed to change the PE in that time

P = 234,213.75/ 45 = 5,204.75 Watts

motor is 5204.75 / 10000 = 0.520475 or 52% efficient

4 0
3 years ago
Suppose that you are standing on a train accelerating at 0.39g. What minimum coefficient of static friction must exist between y
timurjin [86]

Answer:

0.39

Explanation:

In order not to slide, you must have exactly the same acceleration of the train:

a=0.39 g

where

g = 9.81 m/s^2

There is only one force acting on you: the static frictional force that "pulls" you forward, and it is given by

F_s = \mu_s mg

According to Newton's second law, the net force acting on you (so, the frictional force) must be equal to your mass times the acceleration, so we have

F= ma = \mu_s mg

from which we find

\mu_s = \frac{a}{g}=\frac{0.39 g}{g}=0.39

so, the minimum coefficient of static friction must be 0.39.

5 0
3 years ago
An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow.
laila [671]

Answer:

300 N

Explanation:

The net force acting on the arrow is given by Newton's Second Law:

F=ma

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

F=(0.06 kg)(5,000 m/s^2)=300 N

7 0
3 years ago
A beam of protons is moving in the x direction with a speed of 10.6 km/s through a region in which the electric field is perpend
nataly862011 [7]

Answer:

E= 8501.2

Explanation:

Given Data;

Speed = 10.6 km/s = 10.6*10^3 m/s

Magnitude = 0.802 T

The magnitude of the electric field is calculated using the formula;

q E = q v B

E = v B

   = 10.6 *10^3 * 0.802

   = 8501.2

The direction of the electric field will point along the negative z-axis

7 0
3 years ago
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