Answer:
90 m/s
8100 m
Explanation:
Given:
v₀ = 0 m/s
a = 0.5 m/s²
t = 3 min = 180 s
Find: v and Δx
v = at + v₀
v = (0.5 m/s²) (180 s) + 0 m/s
v = 90 m/s
Δx = v₀ t + ½ at²
Δx = (0 m/s) (180 s) + ½ (0.5 m/s²) (180 s)²
Δx = 8100 m
Answer:
The work done is zero
Explanation:
No work is performed or required in moving the positive charge from point A to point B
The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.
The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.
Distance traveled = Velocity × Time
Given in the question
Velocity of the plane = 1200 Km/h
Time Traveled = 2.5 h
Put in the value, we get
Distance traveled = 1200 × 2.5
Distance traveled = 3000 Km
Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
LEARN MORE ABOUT VELOCITY HERE:
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Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
Now we take the arctan or inverse tan of 1/2.
