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3 years ago

Can somebody help???

Mathematics

2 answers:

julsineya [31]3 years ago

7 0

Answer:

2.10 & 2.14

Step-by-step explanation:

its basic adding by 2 yk

Oduvanchick [21]3 years ago

4 0

Answer:

first box - 2.10

second box - 2.14

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System of conics help

ZanzabumX [31]

Answer:

Solutions are (6,3) and (-2,3).

Step-by-step explanation:

From the first equation given we can write:

$(x-2)^{2} = 16-(y-3)^{2}\\$

substituting for $(x-2)^{2}$ in the second equation given we get

$\frac{16-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} = 1$

$\frac{-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} =0$

∴ y=3

Putting y=3 in the first equation we get

$(x-2)^{2} = 16$

x-2 = ±4

Hence x=6 or x=-2.

7 0

3 years ago

Use the definition of Taylor series to find the Taylor series, centered at c, for the function. f(x) = sin x, c = 3π/4

anyanavicka [17]

Answer:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Step-by-step explanation:

Given

$f(x) = \sin x\\$

$c = \frac{3\pi}{4}$

Required

Find the Taylor series

The Taylor series of a function is defines as:

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

We have:

$c = \frac{3\pi}{4}$

$f(x) = \sin x\\$

$f(c) = \sin(c)$

$f(c) = \sin(\frac{3\pi}{4})$

This gives:

$f(c) = \frac{1}{\sqrt 2}$

We have:

$f(c) = \sin(\frac{3\pi}{4})$

Differentiate

$f'(c) = \cos(\frac{3\pi}{4})$

This gives:

$f'(c) = -\frac{1}{\sqrt 2}$

We have:

$f'(c) = \cos(\frac{3\pi}{4})$

Differentiate

$f"(c) = -\sin(\frac{3\pi}{4})$

This gives:

$f"(c) = -\frac{1}{\sqrt 2}$

We have:

$f"(c) = -\sin(\frac{3\pi}{4})$

Differentiate

$f"'(c) = -\cos(\frac{3\pi}{4})$

This gives:

$f"'(c) = - * -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

So, we have:

$f(c) = \frac{1}{\sqrt 2}$

$f'(c) = -\frac{1}{\sqrt 2}$

$f"(c) = -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

becomes

$f(x) = \frac{1}{\sqrt 2} - \frac{1}{\sqrt 2}(x - \frac{3\pi}{4}) -\frac{1/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{1/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Rewrite as:

$f(x) = \frac{1}{\sqrt 2} + \frac{(-1)}{\sqrt 2}(x - \frac{3\pi}{4}) +\frac{(-1)/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{(-1)^2/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Generally, the expression becomes

$f(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Hence:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

3 0

3 years ago

A desk is 39 inches wide. What is the width in yards

Stolb23 [73]

Answer:

1.0833 yd

Step-by-step explanation:

Inches Yards

37" 1.0278 yd

38" 1.0556 yd

39" 1.0833 yd

40" 1.1111 yd

Have a great day! :D

4 0

3 years ago

HELP HELP HELP!!!!!!!!!!!!!!!!!!!!!!!!!

bagirrra123 [75]

A, C, and D
Hope this helps :)
Can I have brainliest

4 0

3 years ago

Read 2 more answers

Write an equation for a direct variation that includes the point (3, 18)

erma4kov [3.2K]

Direct variation means that the line goes through the origin of the graph, so you know that the line must go through point (0,0). Using that along with the given point, you can find the slope of the line.

m = $\frac{y_2 - y_1}{x_2 - x_1}$
m = $\frac{18 - 0}{3 - 0}$
m = $\frac{18}{3}$
m = 6

Now that you know the slope of the line you are looking for is 6, you can plug that into a point-slope form equation and find the equation of your line.

y - y_1 = m (x - x_1) Plug in either set of coordinate. I chose (3, 18).
y - 18 = 6 (x - 3) Use he Distributive Property
y - 18 = 6x - 18 Add 18 to both sides
y = 6x

The equation of a direct variation line that includes the point (3, 18) is y = 6x.

3 0

3 years ago