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2 years ago

9

If F(x) = 3x + 10x and g(x) = 5x - 3, find (f+g)(x)

1 answer:

Ugo [173]2 years ago

5 0

(f+g)(x) represents the sum of the two functions f(x) and g(x).

Arrange these functions vertically and add up like terms:

<span> f(x) = 3x + 10
</span><span>+g(x) = 5x - 3
-----------------------
(f+g)(x) = 8x + 7

Please note: You've typed in "</span><span>F(x) = 3x + 10x and g(x) = 5x - 3."
I doubt that F(x) actually equals 3x + 10x. Please ensure that you have copied down the original problem correctly. Come back once you've done that, so that we can finish this problem solution.</span>

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A school director must randomly select 6 teachers to part in a training session. There are 34 teachers at school. In how many di

prohojiy [21]

Answer:

Total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

Step-by-step explanation:

It is given that total number of teachers at a school is 34.

The school director must randomly select 6 teachers to part in a training session.

$^nC_r=\frac{n!}{r!(n-r)!}$

Where, n is total possible outcomes and r is number of selected outcomes.

Total teachers = 34

Selected teachers =6

Total number of possible ways to select 6 teachers from 34 teacher is

$^{34}C_6=\frac{34!}{6!(34-6)!}$

$^{34}C_6=\frac{34\times 33\times 32\times 31\times 29\times 28!}{6!(28)!}$

$^{34}C_6=1344904$

Therefore total possible ways to select 6 teachers from 34 teacher are $^{34}C_6=1344904$ .

7 0

2 years ago

NEED HELP ASAP, QUICK I NEED THE AREA PLZ!!!

pashok25 [27]

Use a= $\pi$ r^2 (r represents your radius of 4 feet)

$\pi$ (4^2)
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2 years ago

I need help with these two problems

erastova [34]

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2 years ago

What are the steps to solving this? 70-8x=56+x

guapka [62]

Answer:

x = 14/9

Step-by-step explanation:

70 - 8x = 56 + x

- 8x - x = 56 - 70

- 9x = - 14

- x = - 14/9

x = 14/9

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3 years ago

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a square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between the squares

Vlad [161]

5x7=35
your answer is 35 hope i helped

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3 years ago

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