Answer:
I assume AC = 49.89 since the number is cut off
Step-by-step explanation:
tangent(degree) = opposite / adjacent
To find AC, you can set up tan(29) = AC / CB
tan(29) = AC / 90 (the picture is cutted off, so I assume....)
= AC
Answer:
Slope=2.2/5.5 or 0.4
Step-by-step explanation:
slope = (y2-y1)/(x2-x1)
Hence:
slope=(4.4-2.2)/(11-5.5)
slope=2.2/5.5=0.4
The area of the triangle is
A = (xy)/2
Also,
sqrt(x^2 + y^2) = 19
We solve this for y.
x^2 + y^2 = 361
y^2 = 361 - x^2
y = sqrt(361 - x^2)
Now we substitute this expression for y in the area equation.
A = (1/2)(x)(sqrt(361 - x^2))
A = (1/2)(x)(361 - x^2)^(1/2)
We take the derivative of A with respect to x.
dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]
dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]
Now we set the derivative equal to zero.
(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0
-2x^2 + 361 = 0
-2x^2 = -361
2x^2 = 361
x^2 = 361/2
x = 19/sqrt(2)
x^2 + y^2 = 361
(19/sqrt(2))^2 + y^2 = 361
361/2 + y^2 = 361
y^2 = 361/2
y = 19/sqrt(2)
We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
Answer:
angle1=70
angle2=65
angle4=115
angle7=45
angel6=45
angle5=45
Step-by-step explanation:
110+angle1 = 180
angle1 =180-70
angle1 = 70
115+angle2=180
angle2=180-115
angle2=65
angle4=115 because lines are parallel
angle1+angle2+angle7=180 because triangle
70+65+angle7=180
135+angle7=180
angle7=180-135
angle7=45
angel6=45
angle5=45
Answer:
C
Step-by-step explanation:
