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3 years ago

Please help me with my science

Physics

2 answers:

gavmur [86]3 years ago

5 0

Answer:

can you type it

Explanation:

White raven [17]3 years ago

5 0

Answer:

Explanation:

1 The fault is younger than layer A because rock layers are always older than the faults they contain. How could a geologist use the fossil in rock layer B to date a rock layer in another location? ... Geologists can use index fossils to match rock layers at locations that are far apart.

5 h

6 b

9 f

12 g

11 a

7 e

8 c

10 d

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50%

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What happens to hotter air in the atmosphere?

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If you walk across a nylon rug and then touch a large metal object such as a doorknob you may get a spark and a shock. Why does

k0ka [10]

Answer:

Explanation:

You are more likely to be shocked during dry days than humid days because during humid days more water is in the air, and water being a good conductor helps the air absorb some of those charges from you, while during dry days there is less water in the air and hence the charges build up since they are not absorbed.

You are less likely to be shocked when you touch a small metal object because smaller metal objects like a paper clip have less space to accept net charge.

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3 years ago

A 1000kg roller coaster begins at 10m tall hill with initial velocity of 6m/s and travels down until a second hill. 1700J is tra

nadezda [96]

Answer:

The maximum height could be 10.6 meters.

Explanation:

For this kind of exercise, we use the general principle for conservation of mechanical energy (E) that states:

$E_1+W_f=E_2$ (1)

That means the mechanical energy an object has on a point 2 should be equal to the mechanical energy on a point 1 plus the energy transformed into heat due friction denoted as Wf (It is negative because is lost). In our case point 1 is the point where the roller coaster begins and point 2 is at the second hill. Tola mechanical energy is the sum of potential gravitational energy and kinetic energy, so (1) is :

$K_{1}+U_{1}+W_{f}=K_{2}+U_{2}$

with K the kinetic energy and U the potential energy, remember potential energy is mgh and kinetic energy is $\frac{mv^2}{2}$ with m the mass, v the velocity and h the height, then:

$\frac{mv_1^2}{2}+mgh_1+W_{f}=\frac{mv_2^2}{2}+mgh_2$

Solving for h_2:

$h_2=\frac{\frac{mv_1^2}{2}+mgh_1+W_{f}-\frac{mv_2^2}{2}}{mg}=\frac{\frac{(1000)(6)^2}{2}+(1000)(9.8)(10)-1700-\frac{(1000)(4.6)^2}{2}}{(1000)(9.81)}$

$h_2=10.6 m$

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3 years ago

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Theres: the vacuole, nucleus, rough endoplamid reticulum, smooth endoplasmic reticulum, cell memebrane, cell wall, chloroplast, mitochondria, golgi apperatus, lysosomes, and ribosomes

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3 years ago