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vampirchik [111]
3 years ago
14

You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While

there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 445 N in the rope.
If Sneezy hangs from a similar rope while delivering presents at the earth's equator, what will the tension in it be?
Physics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

Explanation:

The question here is that if sneezy hands from a similar rope while delivering presents at the earth's equator, what will be the tension in the rope be. Here is the solution:The tension on the rope when it is at pole, T= 455 NTo find, the tension, t= mgTo solve for mass, m= t/g. Substituting this we have, m=455/9.8. m=46.43 kgAssume that the downwards acceleration is, a= -46.43 m/s^2.T = mg + maT = (46.43 kg) ( 9.8 m/s^2) - (46.43 kg) (-46.43 m/s^2)T = 455.01 kg-m/s^2 - -2155.74 kg-m/s^2T = 2610.75 kg-m/s^2 = 2610.75 N

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The solution for this problem is:

 
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Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

<u>Given the following data;</u>

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First of all, we would solve for momentum;

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Momentum, M1 = 1232 × 25.6

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R² = M1² + M2²

R² = 31539.2² + 35490²

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Angle = tan¯¹(31539.2/35490)

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