A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2
B: (x - 5i)^2
= (x + - 5i)(x + - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2
C: (x - 5i)(x + 5i)
= (x + - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2
D: (x + 10i)(x - 15i)
= (x + 10i)(x + - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
= - 150i^2 + 5ix + x^2
Hope that helps!!!
10 to the 5th power is 100,000. 2 X 5 is 10.
10 X 100,000 is one million.
the answer is 1,000,000. (one million)
Answer:
not me :)
Step-by-step explanation:
because I didnt play among us yet !
Well you want 100% + 3.2% = 103.2%
103.2% = 103.2/100= 1.032
Answer:
<em>1) y = (x-3)²-12</em>
<em>2) y = 5(x-2)²-9 </em>
Step-by-step explanation:
Given the quadratic expressions
y=x²-6x-3
We are to transform it in the form y=ax²+bx+c
y=(x²-6x)-3
Complete the square of the expression in parenthesis
y = (x²-6x + (6/2)² - (6/2)²)-3
y = (x²-6x+3²-3²)-3
y = (x²-6x+9-9)-3
y = (x²-6x+9)-12
y = (x²-3x-3x+9)-12
y = x(x-3)-3(x-3)-12
y = (x-3)(x-3)-12
y = (x-3)²-12
Hence the transformation is y = (x-3)²-12 where a = 1 and k = -12
For the quadratic equation
y=(5x²-20x)-5
y = 5(x²-4x)- 5
Complete the square of the expression in parenthesis
y = 5(x²-4x+4-4)- 5
y = 5(x²-4x+4)-9
y = 5(x-2)²-9
<em>Hence the transformation is y = 5(x-2)²-9 where a = 5 and k = -9</em>
