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lesya692 [45]
3 years ago
8

Please Help. For the best Answer I will give brainiest. And this is 30 points.

Chemistry
2 answers:
Butoxors [25]3 years ago
3 0
Agreed with the other comment
Pani-rosa [81]3 years ago
3 0
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Answer:

elements

Explanation:

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3 years ago
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What is rust and give two methods that can be usedto prevent ​
SOVA2 [1]

Answer:

rust is a substance formed on iron coated when it reacts with water and its miosture.

two general method are--

1.after u make any object of iron wet make it dry fast.

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4 years ago
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A 0.15 mol sample of H2S is placed in a 10 L reaction vessel and heated to 1132◦C. At equilibrium, 0.03 mol H2is present. Calcul
Angelina_Jolie [31]

Answer: The value of the equilibrium constant is 0.00009.

Explanation:

Initial moles of  H_2S = 0.15 mole

Volume of container = 10 L

Initial concentration of H_2S=\frac{moles}{volume}=\frac{0.15moles}{10L}=0.015M  

Moles of H_2 at equilibrium= 0.03 mole

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.03moles}{10L}=0.003M [/tex]

The given balanced equilibrium reaction is,

                            2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initial conc.           0.015 M                     0     0

 At eqm. conc.    (0.015-2x) M           (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.015-2x)^2}

we are given : 2x= 0.003 M

x= 0.0015 M

Now put all the given values in this expression, we get :

K_c=\frac{(0.003)^2\times 0.0015}{(0.015-0.003)^2}

K_c=0.00009

Thus the value of the equilibrium constant is 0.00009.

8 0
3 years ago
The half-life of na-24 is 15 hours . when there are 1000 atoms of na-24 in a sample , a scientist starts a stopwatch . the scien
marin [14]

125 Each half life it divides by 2 the amount
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500/2=250
250/2=125

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Which is smaller 25 mm or 25cm
umka21 [38]

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25 mm is smaller.

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4 years ago
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