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3 years ago

What are the molality and mole fraction of solute in a 35.9 percent by mass aqueous solution of formic acid (HCOOH)?

Chemistry

1 answer:

sdas [7]3 years ago

7 0

ِAnswer:

1- The molarity of HCOOH = 9.515 M.

2- The mole fraction of HCOOH = 0.18.

Explanation:

1- The molarity of HCOOH:

We can calculate the molarity of HCOOH using the relation:

M = (10pd)/molar mass.

p is the percent by mass of HCOOH = 35.9 %.

d is the specific gravity of HCOOH = 1.22 g/cm³.

Molar mass of HCOOH = 46.03 g/mol.

∴ M = (10pd)/molar mass = (10)(35.9 %)(1.22 gcm³) / (46.03 g/mol) = 9.515 M.

2- The mole fraction of HCOOH:

We can suppose that we have a 100 g solution, that contains 35.9 g of HCOOH and 64.1 g of water.

The mole fraction of HCOOH = (no. of moles of HCOOH) / (no. of moles of HCOOH + no, of moles of water).

no. of moles of HCOOH = mass / molar mass = (35.9 g)/(46.03 g/mol) = 0.78 mol.

no. of moles of water = mass / molar mass = (64.1 g)/(18.0 g/mol) = 3.56 mol.

The mole fraction of HCOOH = (no. of moles of HCOOH) / (no. of moles of HCOOH + no, of moles of water) = (0.78 mol) / (0.78 mol + 3.56 mol) = 0.18.

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Answer:

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Explanation:

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2 years ago

Explain what is water of crystallization

ArbitrLikvidat [17]

Explanation:

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2 years ago

How many grams of Lead(II) nitrate are present in 150.0 mL of an Lead(II) nitrate solution that is 0.07268 M?

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Hey...
Use the molarity formula
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3 years ago

How many grams of NaOH are contained in 5.0*10ml of a0. 77 sodium hydroxide solution

Solnce55 [7]

Answer:

1.54grams

Explanation:

Molarity of a solution = n/V

Where;

n = number of moles (mol)

V = volume (L)

Based on the information given in this question;

Volume of NaOH solution = 5.0 × 10ml

= 50ml = 50/1000 = 0.050 L

Molarity = 0. 77 M

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0.77 = n/0.05

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mole (n) = mass/molar mass

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2 years ago