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Fiesta28 [93]
3 years ago
6

If a chemical with a toxicity level of 1 is mixed with a different chemical with a toxicity level of 1, the combined effect of e

xposure to the mixture is 1. This is an example of chemical mixtures interacting through:
a. amplification
b. feedback loop
c. antagonism
d. synergy
e. additivity
Chemistry
1 answer:
ollegr [7]3 years ago
7 0

Answer:

c. antagonism

Explanation:

The toxic effect is that produced by one or several toxic agents on an organism, population or community that is manifested by biological changes. Its degree is assessed by an intensity or severity scale and its magnitude is related to the dose (amount of substance administered, usually expressed per unit of body weight) or the concentration (substance applied in the medium) of the toxic agent.

The effect can be:

- Quantum: consisting of the presence or absence of a characteristic (eg death or existence of tumors).

- Lethal: death by direct action as a result of exposure to a certain concentration of a toxic agent.

- Sublethal: occurs below the level that causes death as a direct result of exposure to a certain concentration of a toxic agent.

- Acute: that caused by the action of chemical substances on living organisms, which manifests rapidly and severely (after a short period of exposure: 0 - 96 h, typically.).

- Chronic: one that occurs, in general, after a prolonged period of exposure (usually manifests after days or years, depending on the species).

- Additive: the magnitude of the effect or simultaneous response of two or more substances is equal to the sum of the effects or responses of each.

- Combined: when two or more substances applied at the same time produce different effects or have different modes of action.

- Enhancement or synergism: when the toxicity of a mixture of chemical agents is greater than expected by the simple sum of the toxicities of the individual agents present in the mixture.

- Inhibition or antagonism: when the toxicity of a mixture of chemical agents is lower than expected by the simple sum of the toxicities of the individual agents present in the mixture.

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7 0
2 years ago
Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actua
GrogVix [38]

The value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

The rust forms when 4.85X10³ kJ of heat is released is 888.916 g.

<h3>Chemical reaction:</h3>

4 Fe + 3O2 ------ 2Fe2O3

∆H = -1.65×10³kJ

A) Given,

mass of iron = 0.250kg = 250 g

<h3>Calculation of number of moles</h3>

moles = given mass/ molar mass

= 250/ 55.85 g/mol.

= 4.476 mol

As we know that,

For the rusting of 4 moles of Fe, ∆H = -1.65×10³kJ

For the rusting of 4.476 moles of Fe ∆H required can be calculated as

-1.65×10³kJ × 4.476 mol/ 4mol

∆H required = -1.846 × 10³kJ

Now,

when 2 mol of Fe2O3 formed, ∆H = - 1.65×10³kJ

It can be said that,

-1.65×10³kJ energy released when 2 mol of Fe2O3 formed

So, -4.6 × 10³kJ energy released when 2 mol of Fe2O3 formed

= 2 × -4.6 × 10³kJ / -1.65×10³kJ

= 5.57 mol of Fe2O3 formed

Now,

mass of Fe2O3 formed = 5.57 mol × 159.59 g/mol

= 888.916 g

Thus, we calculated that the rust forms when 4.85X10³ kJ of heat is released is 888.916 g. and the value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

learn more about ∆H:

brainly.com/question/24170335

#SPJ4

DISCLAIMER:

The given question is incomplete. Below is the complete question

QUESTION:

Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actual process requires water, but a simplified equation is 4Fe(s) + 3O₂(g) → 2Fe₂O₃(s) ΔH = -1.65×10³kJ

a) What is the ∆H when 0.250kg iron rusts.

(b) How much rust forms when 4.85X10³ kJ of heat is released?

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1 year ago
Which of the following is the reason that the lemurs shown below share many traits?
ycow [4]
A. They have similar DNA
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Which of the following is true about elements?
kondor19780726 [428]

Answer:

The first one

Explanation:

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6 0
3 years ago
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

4 0
3 years ago
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