How many cubic centimeters are in 5.2 liters?
1 answer:
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Answer:
Acceleration(a) =
v = final velocity = 5.5 m/s
u = initial velocity = 3 m/s
t = time = 9s
(approx)
The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
where a is the acceleration. Using the data of the problem, we can find a:
So now we can solve the 3 parts of the problem.
a) power output at t=2.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
b) power output at t=4.0s
The velocity at t=4.0 s is
the kinetic energy of the sprinter is
and so the power output is
c) Power output at t=6.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
where a is the acceleration. Using the data of the problem, we can find a:
So now we can solve the 3 parts of the problem.
a) power output at t=2.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
b) power output at t=4.0s
The velocity at t=4.0 s is
the kinetic energy of the sprinter is
and so the power output is
c) Power output at t=6.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
Answer:
w =3416 rad/min
Explanation:
The angular speed of the wheels in radians can be defined as follows:
where
w = angular speed
r = radius of the wheel
s =distance traveled per minute
in this case we have
r = 34/2 inches = 17 inches
s = (55 mi/hr) (5280 ft/mi) (12 in/ft) (1hr/60min) = 58,080 inches/min
Therefore, w = 58,080/ 17 = 3416 rad/min