Answer:
1250
Explanation:
Let's look at this in a simple manner, because it is.
The crane weights 250Kg. Okay.
Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)
Since F = m * a
F = 250 * 10
F = 2500
Now we know that the downward Force is 2500N.
To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be
.
Therefore, the force pulling the box in the cable's direction is:

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Answer:
x=7227
y=1678
(7227,1678)
Explanation:
Ok, check the picture I attached you, because of the problem don't give us aditional information, let's asume that the projectile is fired from an initial position x=0 and y=0. Now let's use projectile motion equations, but firs let's find the initial velocity components in x-axis and y-axis:


Now, let's find the x coordinate with this equation:

Finally asumming a gravity constant g=9.8, let's find the y coordinate with the next equation:

