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Ede4ka [16]
3 years ago
12

4: Question 2 - 10.0 pts possible

Physics
1 answer:
Orlov [11]3 years ago
8 0

Answer:

5. All of the statements are true; non is false

Explanation:

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Assuming that the angle is the same for both ropes, then D. is the answer.  You have to consider also if the ropes are close together or far apart and if the force to move the object is in line with the ropes or perpendicular to them.
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What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 2.1 g that has been charged to -
Liula [17]

Answer:

Electric field, E=6.86\times 10^6\ N/C

Explanation:

It is given that,

Mass of sphere, m = 2.1 g = 0.0021 kg

Charge, q=-3\ nC=-3\times 10^{-9}\ C

We need to find the magnitude of electric field that balances the weight of a plastic spheres. So,

ma=qE

a = g

E=\dfrac{mg}{q}

E=\dfrac{0.0021\ kg\times 9.8\ m/s^2}{-3\times 10^{-9}\ C}

E=6860000\ N/C

or

E=6.86\times 10^6\ N/C

Hence, the magnitude of electric field that balances its weight is 6.86\times 10^6\ N/C. Hence, this is the required solution.

4 0
3 years ago
A spherical submersible 1.84 m in radius, armed with multiple cameras, descends under water in a region of the Atlantic Ocean kn
Drupady [299]

Answer:

23932242.5 Pa

Explanation:

P_a = Atmospheric pressure = 1.013\times 10^5\ Pa

P_w = Pressure of seawater

\rho = Density of sea water = 1.025\times 10^3\ kg/m^3

h = Depth of shipwreck = 2.37\times 10^3\ m

g = Acceleration due to gravity = 9.81 m/s²

The absolute pressure is given by

P_{ab}=P_a+P_w\\\Rightarrow P_{ab}=1.013\times 10^5+1.025\times 10^3\times 9.81\times 2.37\times 10^3\\\Rightarrow P_{ab}=23932242.5\ Pa

The absolute pressure at the depth of the shipwreck is 23932242.5 Pa

5 0
3 years ago
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