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motikmotik
3 years ago
5

How to convert 1gcm⁻³ in to kg⁻³??

Physics
1 answer:
dimulka [17.4K]3 years ago
3 0

The answer is 0.001 , 1000 grams = 1 Kilograms

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Smaller bits of rock that pass through the atmosphere and slam into Earth's surface are called
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A bullet of mass m = 40~\text{g}m=40 g, moving horizontally with speed vv, strikes a clay block of mass M = 1.35M=1.35 kg that i
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Answer:

 v > 133.5 m/s

Explanation:

Let's analyze this problem a little, park run a complete circle we must know the speed of the system at the top of the circle.

Let's start by using the concepts of energy to find the velocity at the top of the circle

Initial. Top circle

    Em₀ = K + U = ½ m v² + m g y

If we place the reference system at the bottom of the cycle y = 2R = L

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final. Low circle

    Em_{f} = K = ½ m v₁²

    Emo =  Em_{f}

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    v₁² = v² + 2 g L

The smallest value that v can have is zero, with this value the bullet + block system reaches this point and falls, with any other value exceeding it and completing the circle. Let's calculate for this minimum speed point

     v₁ = √2g L

We already have the speed system at the bottom we can use the moment

Starting point before crashing

    p₀ = m v₀

End point after collision at the bottom of the circle

    p_{f} = (m + M) v₁

The system is formed by the two bodies and therefore the forces to last before the crash are internal and the moment is conserved

    p₀ = p_{f}

    m v₀ = (m + M) v₁

   v₀ = (m + M) / m v₁

Let's replace

   v₀ = (1+ M / m) √ 2g L

Let's reduce to the SI system

   m = 40 g (kg / 1000g) = 0.040 kg

Let's calculate  

    v₀ = (1 + 1.35 / 0.040) RA (2 9.8 0.753)

    v₀ = 34.75 3.8417

    v₀ = 133.5 m / s

the velocity must be greater than this value

    v > 133.5 m/s

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