The complete sentence is:
In a third class lever, the distance from the effort to the fulcrum is SMALLER the distance from the load/resistance to the fulcrum.
In fact, in a third class lever, the fulcrum is on one side of the effort and the load/resistance is on the other side, so the effort is located somewhere between the two of them. This means that the distance effort-fulcrum is smaller than the distance load-fulcrum.
Answer:
5 is the tripoid stand
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To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,
Here,
v = Velocity
= Linear density (Mass per unit length)
T = Tension
Rearranging to find the Period we have that
As we know that speed is equivalent to displacement in a unit of time, we will have to
Therefore the tension is 5.54N
The maximum force that the tires can exert on the road before slipping is 16200 N.
From the information in the question;
The coefficient of static friction = 0.9
The mass of the car = 1800 kg
Using the formula;
μ = F/R
μ = coefficient of static friction
F = force on the tires
R = the reaction force
But recall that the reaction is equal in magnitude to the weight of the car.
W=R
Hence; R = 1800 kg × 10 ms-2 = 18000 N
Making F the subject of the formula;
F = μR
Substituting values;
F = 18000 N × 0.9
F = 16200 N
Hence, the maximum force that the tires can exert on the road before slipping is 16200 N.
Learn more: brainly.com/question/18754989
