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pantera1 [17]
3 years ago
6

TIMED TEST WITH ONLY A FEW MINUTES LEFT, HELP!!

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

width = 1 unit, length = 8 units

Step-by-step explanation:

julia-pushkina [17]3 years ago
7 0

Step-by-step explanation:

width 1 unit

length 8 units

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What is the value of the expression 3 squared times the quantity of 2 cubed + 4 all divided by 2 squared?
antoniya [11.8K]

Answer:

27

Step-by-step explanation:

Put this into numbers:

\frac{3^2*(2^3+4)}{2^2}

Use Order of Operations to simplify. First, you would do the stuff in parentheses which is:

2^3+4

Inside of those parentheses first simplify the exponents:

8 + 4

Now add

12

So the new equation is:

\frac{3^2*12}{2^2}

The next step is to simplify the exponents

\frac{9*12}{4}

Multiply out the top

\frac{108}{4}

Divide this

27

5 0
3 years ago
Find the area of this figure
vovikov84 [41]
Thirty seven square units
4 0
3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations
dimulka [17.4K]

Answer:

a. 0.80

b. $80

Step-by-step explanation:

a. The expected value, E(Y) is the sum of: [(each of the possible outcomes) × (the probability of the outcome occurring)]. In more concrete terms, the expectation is what you would expect the outcome of an experiment to be on average:

E(Y)=S_yP(Y=y)\\\\=0\times 0.5+1\times 0.25+2\times 0.20+3\times 0.05\\\\=0.80

Hence the expected value E(Y) is 0.80

b. From a above we have the expectation as  E(Y)=0.80.

-The expected amount is calculated by multiplying  expectation by the surcharge:

Ex \ Amount= E(Y)\times surcharge\\\\=0.80\times 100\\\\=80

Hence, the expected amount of surcharge is $80

4 0
3 years ago
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3 0
3 years ago
Read 2 more answers
Solve for the largest value of $x$ such that $5(9x^2+9x+10) = x(9x-40).$ Express your answer as a simplified common fraction.
irinina [24]

Hello, please consider the following.

\begin{aligned}5(9x^2+9x+10) &= x(9x-40)\\&=9x^2-40x\end{aligned}\\\\ 45x^2+45x+50=9x^2-40x\\\\ (45-9)x^2+(45+40)x+50=0\\\\ 36x^2+85x+50=0

We can estimate the discriminant, and then, the solutions and we take the largest one.

\Delta=b^2-4ac=85^2-4*36*50=25=5^2\\\\x_1=\dfrac{-85-5}{2*36}=\dfrac{-18*5}{18*4}=\dfrac{-5}{4}\\\\x_2=\dfrac{-85+5}{2*36}=\dfrac{-80}{72}=\dfrac{-8*10}{8*9}=\boxed{\dfrac{-10}{9}}

Thank you

7 0
3 years ago
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