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Stolb23 [73]
2 years ago
11

(x + 1)^2 -8 (x-1 +16)

Mathematics
1 answer:
tia_tia [17]2 years ago
5 0

Answer: x2−6x−119

Step-by-step explanation:

provided in the screenshot below

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Integer and rational numbers
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The ratio of red foxes to gray wolves in a national park is 3 to 7.
Brums [2.3K]

Answer:

c

Step-by-step explanation:

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5 0
2 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m
Olenka [21]

Consider \Delta AOB\cong \Delta BDC.

Given:

\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.

To find:

The length of BC.

Solution:

We have,

\Delta AOB\cong \Delta BDC

We know that the corresponding parts of congruent triangles are congruent (CPCTC).

AB=BC                   (CPCTC)

5\ m=BC

The length of BC is 5 m. Therefore, the correct option is A.

5 0
2 years ago
What is the molar solubility of magnesium fluoride in a solution that is 0.40 m f− ions? the ksp of mgf2 is 6.4 × 10−9. hints wh
velikii [3]
<span>Answer: MgF2 ====⇒ Mg+2 + 2F- Ksp = [Mg+2][F-]^2 Let S = molar solubility of MgF2 [Mg+2] = S ; [F-] = 2s Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S 6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present. 6.4 x 10^-9 = S(0.40)^2 S = 4.0 x 10^-8 Molar solubility = 4.0 x 10^-8</span>
6 0
3 years ago
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