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Naddika [18.5K]
3 years ago
8

Cnidarians are another major group of invertebrates. Jellyfish, coral, hydra and anemone are examples of cnidarians. They have s

oft bodies and no heads. They have stinging tentacles that they use for defense and to capture prey. Cnidarians have radial symmetry. That means that their parts are arranged around a center. If you were to draw a line to cut them in half in any direction, the two sides will always match. Radial symmetry is often a characteristic of more simple animals than bilateral symmetry, where there is only one line you could draw to make two sides match. With bilateral symmetry, different body parts may have different functions. With radial symmetry, the entire body may perform all life functions.
Jellyfish do not have (what?)

a. heads.
b. tentacles.
c. symmetry.
d. soft bodies.
Mathematics
1 answer:
zvonat [6]3 years ago
5 0
A. heads


A jellyfish has no ears or eyes or nose and no brain or heart. They do not even have a head as their body is almost totally made of water and is soft having no bones at all.
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A trout lurking 32 cm below the surface of a lake spies an insect flying 17cm above the lake. How many centimeters would the tro
Bumek [7]

Answer:

The Trout will have to jump 49 cm in order to catch the insect

Step-by-step explanation:

Here, we want to calculate the distance the Trout has to jump in order to catch the Insect

To calculate this, we need to know the difference in the distances

From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake

The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;

17 + 32 = 49 cm

3 0
3 years ago
How many different 6-digit numbers can be formed by arranging the digits in 332345?
Feliz [49]

Answer- 120

Solution-

There are digits to be arranged,they are {3,3,2,3,4,5}. And from those ,3 digits are repeated .

so the total number of distinct number that can be formed = \frac{6!}{3!} = \frac{720}{6} = <em>120</em><em> </em>(ans)


7 0
3 years ago
Use the zero product property to find the solutions to the equation x^2+x-30=12
lukranit [14]

Answer:

Due to there being no negatives in this equation, you can pretty much just eliminate the first 3 answers.


However in working out, here is what I did.

x^2 + x - 30 = 12 (+30) 

= x^2 + x = 42


Then you can conclude that the answer is D, due to 6 x 6 = 36, plus 7 equaling 42. 





8 0
3 years ago
Add the product of 5 and 6 with the product of 3 and 7
ryzh [129]
5x6 = 30
3x7= 21
21+30 = 51

is this what you mean? if so, I'm glad to help
3 0
3 years ago
Read 2 more answers
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
3 years ago
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