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goldfiish [28.3K]
3 years ago
12

Alguien me ayuda pls

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

good

Step-by-step explanation:

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The time you have before finance charges are assessed is called the a. credit limit. c. APR. b. incentive. d. grace period.
Tanya [424]

Answer:

The time you have before finance charges are assessed is called the Grace period

option-D

Step-by-step explanation:

we know that

Grace period is the extra time given to customer to pay amount before finance charges

But once grace period passes , customer will have to pay extra fee or penalty with interest with passing days

So,

The time you have before finance charges are assessed is called the Grace period

So,

option-D

6 0
3 years ago
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
A cell phone is on sale for $205 after a 20% off discount. What was the original price of the phone?
Leni [432]

Answer:

256.25

Step-by-step explanation:

if you have a 20% discount then you are paying 80% if the original cost.

so 80% of the original price is 205

.80x = 205

x = 205/.80

7 0
3 years ago
Help please!!! Pre-calculus
Anvisha [2.4K]

Answer:

P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))

Step-by-step explanation:

P ( 3, - pi/3)

We can circle 2pi n around the circle and be back at the same polar coordinate

P ( 3, - pi/3 + 2 pi n)

or we can flip the radius to a negative and add pi to the theta

P ( -3, - pi/3 + pi)

Then we can circle 2pi n around the circle and be back at the same polar coordinate

P ( -3 , -pi/3 + 2 pi n +pi)

P ( -3 , -pi/3 + pi(2 n +1))

6 0
3 years ago
3.. please help!!!!!!!!!!!
mario62 [17]

Answer: lalala

Step-by-step explanation:

7 0
3 years ago
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