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MariettaO [177]
3 years ago
9

The width of a rectangle is five more than two times the length. The perimeter of the rectangle is 106 inches. What are the dime

nsions of the rectangle?
Mathematics
1 answer:
schepotkina [342]3 years ago
3 0
Say, width = x

length = 2x +5

(x+2x+5)*2= 6x+10

6x+10=106

x= 96/6=16

Width =16 Mt
Length =37 mt
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Answer:

The answer is C!!

Step-by-step explanation:

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Rename 28 percent as a decimal and fraction in its simplest form.
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28% is 28/100 as a fraction but the simplest form is 14/50 and it can be simplified to 7/25. the decimal is 0.28

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If preimage is (0, 1) . (4, 0), (4, 1) , what are the points after a translation of 3 units up and then a reflection over the -a
yulyashka [42]

Answer:

(0, 4) (-4, 3) (-4, 4)

Step-by-step explanation:

Translation rules:

Units UP - Add to the y-coordinate.

Units DOWN - Subtract from the y-coordinate.

Units RIGHT - Add to the x-coordinate.

Units LEFT - Subtract from the x-coordinate.

--------------------------------------------------------------------------------------------------------------

In this case, the word problem is asking for the points after a translation of 3 units up.

(x, y+3)

(0,1) → (0,4)

(4,0) → (4,3)

(4,1) → (4,4)

--------------------------------------------------------------------------------------------------------------Now it's time to reflect the new points over the y-axis.

When reflecting over the y-axis, the y-coordinate remains the same, but the x-coordinate becomes the opposite value. (-x, y)

(0,4) → (0,4)

(4,3) → (-4,3)

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3 years ago
Order the numbers from greatest to least 56.01, 56.1, 56.011
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56.1, 56.011, 56.01......................
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3 years ago
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Use partial fractions to find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constan
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Answer:

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Step-by-step explanation:

∫x2/x1−20x2−125dx

Should be

∫x²/(x²−20x−125)dx

First of all let's factorize the denominator.

x²−20x−125= x²+5x-25x-125

x²−20x−125= x(x+5) -25(x+5)

x²−20x−125= (x-25)(x+5)

∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx

x²/(x²−20x−125) =x²/((x-25)(x+5))

x²/((x-25)(x+5))= a/(x-25) +b/(x+5)

x²/= a(x+5) + b(x-25)

Let x=25

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a= 125/6

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∫x²/(x²−20x−125)dx

=∫125/6(x-25) -∫5/6(x+5) Dx

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4 years ago
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