3(x−5)/2=2(x+5)/3
Cross-multiply.
(3(x−5))/2=(2(x+5))/3
3(x−5)*(3)=2(x+5)*(2)
9x−45=4x+20
Subtract 4x from both sides.
9x−45−4x=4x+20−4x
5x−45=20
Add 45 to both sides.
5x−45+45=20+45
5x=65
Divide both sides by 5.
5x/5=65/5
x=13
Answer:
y= 1/3x + 3.66
Step-by-step explanation:
Hey you can use Mathaway it's really it will solve anything you want
So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula

so if you were to input it into this equation you would get
a=3
b=4
c=-2
the solution is

the answer is C