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Salsk061 [2.6K]
3 years ago
8

"Using the given information, determine the cost of one no rechargeable alkaline battery; and compare with the cost of one recha

rgeable NiCad battery. *Assumption: The cost of the electricity to recharge the NiCad is negligible (about $0.01). NiCad batteries can be recharged (reused) 100 times. A 4 pack of AA NiCad rechargeable batteries cost $10.80. A 4 pack of AA alkaline non rechargeable batteries cost $3.69. Over the life of the battery, which battery is most cost effective? Group of answer choices The NiCad AA rechargeable battery The AA alkaline non rechargeable battery Both batteries cost are the same Batteries are independent of chemical composition and therefore does not impact consumer cost structures"
Business
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

Over the life of the battery, the battery that is most cost-effective is:

The AA alkaline non rechargeable battery.

Explanation:

a) Data and Calculations:

Number of times that NiCad batteries can be recharged (reused) = 100 times

Cost of a 4 pack of AA NiCad rechargeable batteries = $10.80

Recharging cost = $1 ($0.01 * 100)

Total cost of AA NiCad rechargeable batteries = $11.80

Cost per use = $0.12 ($11.80/100)

Cost of a 4 pack of AA alkaline non rechargeable batteries = $3.69

Cost per use of AA alkaline non rechargeable batteries = $0.04 ($3.69/100)

b) The comparison and the resulting conclusions are based on the assumption that the non rechargeable and the rechargeable batteries enjoy equal useful life.  Therefore, the AA alkaline non rechargeable batteries are also used 100 times.

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"In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-
viva [34]

Answer:

z= \frac{51-37}{7}=2

z= \frac{23-37}{7}=-2

So then as we can see we want the probability that the values would be within 2 deviations from the mean. And from the empirical rule we know that within two deviation from the mean we have at least 95% of the data.

So then we can answer this question like this:

P(23

Or 95%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case we know that the the random variable X represent the number of phone calls answered by each of the 12 receptionists is bell shaped with a mean \mu = 37 and a standard deviation of \sigma = 7.

And for this case we want to find this probability:

P(23

And the best way to solve this is using the z score formula given by:

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Because the z score quantifies how many deviation we are from the mean.

For the value fo 51 we have this:

z= \frac{51-37}{7}=2

And for the 23 we got:

z= \frac{23-37}{7}=-2

So then as we can see we want the probability that the values would be within 2 deviations from the mean. And from the empirical rule we know that within two deviation from the mean we have at least 95% of the data.

So then we can answer this question like this:

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It should be noted that in snowball sampling, after the respondents have been interviewed, theywould be told asked to help identify other people

that also belong to the target population.

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Answer:

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A middle manager refers to an individual who acts as an intermediary between the executive management and the employee working with the company.

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