3 years ago

Find the distance between the two points. 3. (-3, -1), (6, 2)

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Angela has a rectangular piece of paper

3241004551 [841]

Is there a picture of the rectangular piece of paper

3 0

3 years ago

Read 2 more answers

For several months, a restaurant manager collected data on the number of people at a table (p) and the total bill, in dollars (d

Leviafan [203]

The answer will be c. I'm sorry if I'm wrong

4 0

3 years ago

Read 2 more answers

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

Find the difference:

mihalych1998 [28]

Answer:

3 1/2

Step-by-step explanation:

4 1 3

_ - _ = _

6 6 6

Then we simplify. 3 3 1

_ ÷ = _

6 3 2

Then just add your 3 and there 3 1/2 is your asnwer

8 0

3 years ago

I need help with this question please answer as soon as possible

Setler79 [48]

Answer: I think that the answer is D

Step-by-step explanation:

3 0

3 years ago