The answer is C.
I hope this helps.
Answer:
9x+y−5=0 9 x + y − 5 = 0 .
Step-by-step explanation:
The product is: 25x^2-5xy-6y^2
Statement : If the perpendicular bisectors of two sides of a triangle meet at point that belongs to the third side then this is a right angle triangle.
Prove:
Let ABC is triangle,
In which DF and EF are the perpendicular bisectors of legs AB and BC respectively.
That is, ∠ FDB = ∠BEF= 90°
Where, 
Then By the property of the circumcenter,
F must be mid point of leg AC.
That is, DF ║ BC
⇒ ∠ FDB + ∠ DBC = 180° ( the sum of two adjacent angles on the parallel lines by the same transversal is supplementary )
But, ∠ FDB = 90°
⇒∠ DBC = 90°
⇒ ∠ ABC = 90°
That is, Δ ABC is a right angle triangle.
The x-intercept and y-intercept are (-3,0) and (0,4/5).
Given,
-3x-4=-5y-8
We need to find the intercept of the line.
<h3>What are intercepts?</h3>
Intercepts are the points at which the line crosses the axis.
There are two intercepts :
x-intercept - the point at which the line crosses the x-axis.
Here, y = 0.
y-intercept - the point at which the line crosses the y-axis.
Here, x = 0.
The line is -3x - 4 = 5y - 8
Put x = 0,
-3 x 0 - 4 = 5y - 8
0 - 4 = 5y - 8
5y = 8 - 4
y = 4 / 5
So,
( 0, 4/5 ) is the point where the line crosses the y-axis.
This is the y-intercept.
Put y = 0,
-3x - 4 = 5y - 8
-3x - 4 = 5 x 0 - 8
-3x - 4 = 0 - 8
-3x - 4 = 8
3x = -8 - 4
3x = -12
x = -12/4
x = -3
( -3, 0 ) is the point where the line crosses the x-axis.
This is the x-intercept.
Thus x-intercept and y-intercept are (-3,0) and (0,4/5).
Learn more about intercept here:
brainly.com/question/14180189
#SPJ1
