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slava [35]
4 years ago
9

Find the value of x in the parallelogram.

Mathematics
1 answer:
wlad13 [49]4 years ago
5 0

Answer:

Since it's a parallelogram, the length of AD and BC are the same.

Hence, x + 21 = 12x - 1.

x + 21 = 12x - 1

12x - x = 21 + 1

11x = 22

x = 2

Therefore, x = 2.

Step-by-step explanation:

Hope this helped!

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WILL GIVE BRAINLIEST IMMEDIATELY!!!!!!!
ladessa [460]

Answer:

The measure of m∠KNY is;

(D) 105°

Step-by-step explanation:

From the diagram, we have;

The given angle at the circumference = The The angle the arcs makes at the center of the circle

From circle, theorem, angle subtended at the center = Twice the angle subtended at the circumference

Therefore;

Angle ∠D and angle ∠Y = 90°/2 = 45°

Angle ∠O and angle ∠K = 60°/2 = 30°

From angle summation theorem, we have;

m∠KNY + ∠K + ∠Y = 180° (The sum of the interion angles in ΔYNK

∴ m∠KNY = 180° - (∠K + ∠Y)

Plugging in the known values of ∠K and ∠Y gives;

m∠KNY = 180° - (30° + 45°) = 105°

m∠KNY = 105°.

7 0
3 years ago
1.2 Exit Ticket
mestny [16]

Answer:

174

Step-by-step explanation:

Given

132, 145, 97, 112, 128, 82

Required

Estimate amount of students in an art class

This is calculated by obtaining the mean of the given data

Mean = \frac{\sum x}{n}

Where n is the number of observations

So;  n = 6

Mean = \frac{132+ 145+ 97+ 112+  128+  82}{6}

Mean = \frac{696}{6}

Mean = 174.0

<em>Hence, the estimated number of students is 174</em>

4 0
4 years ago
If I charged 30$ a hair cut the whole year how many times would each customer have to come in to get 17,510$
V125BC [204]
You would need to come in 583.6 or 584 times
5 0
3 years ago
If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .
ollegr [7]

Answer:

2y^2-7y+6=0

Step-by-step explanation:

We are given that \alpha and \beta are the zeroes of the polynomial 6y^2-7y+2

y^2-\frac{7}{6}y+\frac{1}{3}

We have to find a quadratic polynomial whose zeroes are 1/\alpha and 1/\beta.

General quadratic equation

x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes

We get

\alpha+\beta=\frac{7}{6}

\alpha \beta=\frac{1}{3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3

Substitute the values

y^2-(7/2)y+3=0

2y^2-7y+6=0

Hence, the quadratic polynomial whose zeroes are 1/\alpha and 1/\beta is given by

2y^2-7y+6=0

4 0
4 years ago
What is the value of sin(A)?
inn [45]

Answer:

sin(A) = \frac{6}{10}  = \frac{3}{5}

3 0
3 years ago
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