You asked to find what price, given ...
... $6.40 = 4% × (what price)
Divide by 4%
... $6.40/0.04 = (what price) = $160.00 . . . . matches selection D)
Step-by-step explanation:
3.60
Answer:
The approximate probability of getting 100000 views or more in January if we assume view counts from day-to-day are independent = 0.22254
Step-by-step explanation:
January has 31 days.
The average number of views per day = 3022 views per day.
In terms of hourly basis, the average number of views = 3022/24 ≈ 126 views per hour
Then we need to find the probability that the number of views in January is equal to or exceeds 100000.
100000 views in January = 100000/31 = 3225.81 ≈ 3226 views per day
On an hourly basis, 3226 views per day ≈ 135 views per hour.
So, mean = λ = 126 views per hour
x = 135 views per hour.
Using Poisson's distribution function
P(X = x) = (e^-λ)(λˣ)/x!
P(X ≥ x) = Σ (e^-λ)(λˣ)/x! (Summation From x to the end of the distribution)
But it's easier to obtain
P(X < x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)
P(X ≥ x) = 1 - P (X < x)
Putting λ = 126 views/hour and x = 135 views/hour in the Poisson distribution formula calculator
P(X ≥ 135) = 0.22254
4n + 2 = 6(1/3n - 2/3)?
Use distributed to remove parenthesis
4n+2=6(1/3n)+6(-2/3)
Solve right side
4n+2=2n-4
Subtract 4n from 2n
4n-2n+2=-4
Simplify
2n+2=-4
Subtract 2 from both sides
2n=-4+2
Simplify
2n= -2
Divide both sides by 2
2n/2=-2/2
And solve
N= -1
Answer:
Okay, i'll help.
Step-by-step explanation:
