Can u please tell and explain

A bicycle rides in a straight line at 1 km at 10

ahrayia [7]

Answer:

avg speed =total distance/total time

total distance =2km (given)

total time=1/10 +1/25=7/50

so avg speed =100/7=14.28

6 0

3 years ago

Given a 45 45 90 prism with index of 1.5, immersed in air. The hypotenuse acts as the reflecting face by TIR. A ray of light ent

Genrish500 [490]

Answer:

83.6°

Explanation:

For the ray to be totally internally reflected, at the boundary, the angle of refraction is 90. Using the law of refraction where

n₁sinθ₁ = n₂sinθ₂ where n₁ = refractive index of prism = 1.5, θ₁ = critical angle in prism, n₂ = refractive index of air = 1 and θ₂ = refractive angle = 90°.

So, substituting these values into the equation,

n₁sinθ₁ = n₂sinθ₂

1.5 × sinθ₁ = 1 × sin90

1.5 × sinθ₁ = 1

sinθ₁ = 1/1.5

sinθ₁ = 0.6667

θ₁ = sin*(0.6667)

θ₁ = 41.8°

So, for total internal reflection, an incidence angle of 41.8° is required. So, a full convergence angle of 2 × 41.8° = 83.6° is required for the whole bundle of rays.

5 0

4 years ago

When developing an experimental design, which action could a scientist take

NNADVOKAT [17]

Answer:

B.Include as many details as possible when writing the conclusion.

This helps improve the quality of their experiment..

_Askmeanything2♡

6 0

3 years ago

A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t

Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

We can find the new volume by using the Ideal Gas Law:

$PV = nRT$

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature

Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

$nR = \frac{P_{1}V_{1}}{T_{1}}$ (1)

And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:

$nR = \frac{P_{2}V_{2}}{T_{2}}$ (2)

By equating (1) with (2):

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

$V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml$

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.

I hope it helps you!

3 0

3 years ago

A quarterback takes the ball from the line of scrimmage, runs backward for 12.1 yds, then runs sideways parallel to the line of

Over [174]

Answer:

The answer is 35.45 yds

Explanation:

You have to picture this to be able to understand it better (see attachment).

Start at the origin which is when the quarterback (QB) takes the ball. He runs backwards 12.1 yards, runs sideways for 19.8 yards (it doesn´t matter if he runs right or left), then he throws the ball forward 41.5 yards. If you look at the attachment, you can see I drew the path that the football followed. And then connected the dots from the origin and finish. The distance between those two points is the magnitude of the resultant displacement.

In order to calculate it, all you need to do is use the Pythagoream theorem, which says that the square of the hypotenuse equals the sum of the squares of the legs a and b of the triangle rectangle.

$R^{2} = a^{2} + b^{2}$ then solve for R
$R = \sqrt{a^{2}+b^{2} }$

In this case, you know the length of leg a to be 19.8 yards which how much it moves sideways. And then, to get the length of leg b, all you need to do is substract how much it moved backwards from the 41.5yards forward displacement. This results in b leg being 29.4 yards long.

Now you have a triangle with:

a = 19.8 yards
b = 29.4 yards

Substituting this numbers in the equation:

$R = \sqrt{19.8^{2}+29.4^{2} }$
R = 35.45 yards

3 0

3 years ago