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maksim [4K]
2 years ago
6

An object has moved through a distance. Can it have zero displacement? Justify your answer.PLEASE I WILL MARKK AS BRAINLIESTT

Physics
1 answer:
DochEvi [55]2 years ago
3 0

Answer:

Explanation:

yes object can move through a distance  and can have zero displacement  

as displacement is the shortest distance between two points eg: if a person has moved a distance of 20 m and comes back to his original place by moving back 20m in such a case  distance moved by the person is 40m but his displacement is 0 as shortest distance covered by him is 0 as he is in his original place

Yes, it is possible for a body to have traveled a distance yet have a displacement of zero.

Distance traveled by a body is the length of the path covered by it.

On the other hand displacement of a body is the shortest distance between the initial and the final point of a body.

When a body is traveling such that it ends at the point from where it started its journey, it covers a distance but the displacement of the body is zero.

So a body that has moved through a distance can have zero displacement.

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The x coordinate of an electron is measured with an uncertainty of 0.200 mm . What is vx, the x component of the electron's velo
Vikentia [17]

Answer:

Velocity of electron along x direction is 57.9 m/s

Explanation:

The uncertainty in x coordinate of electron, Δx = 0.200 mm = 0.2 x 10⁻³ m

Let vₓ be the x component of electrons velocity.

The uncertainty in x component of electrons momentum is:

Δpₓ = mΔvₓ

Here m is mass of the electron.

The uncertainty in velocity x component is 1% i.e. 0.01.

So, the above equation can be written as :

Δpₓ = 0.01mvₓ    ....(1)

The minimum uncertainty principle is:

\Delta x\Delta p_{x} = \frac{h}{2\pi }    ....(2)

Here h is Planck's constant.

From equation (1) and (2),

\Delta x\times0.01m v_{x} = \frac{h}{2\pi }

Substitute 0.2 x 10⁻³ m for Δx, 9.1 x 10⁻³¹ kg for m and 6.626 x 10⁻³⁴ m²kg/s in the above equation.

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8 0
3 years ago
Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s
adell [148]

Answer:

\theta = 20\ rev

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

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\alpha = \dfrac{2-0}{7}

\alpha = 0.286\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1

2^2 = 0^2 + 2\times 0.286 \times \theta_1

\theta_1 = 7 rev

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{0-2}{13}

\alpha = -0.154\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2

0^2 = 2^2 + 2\times (-0.154) \times \theta_2

\theta_2 = 13 rev

total revolution in this case

\theta = \theta_1 + \theta_2

\theta =7 +13

\theta = 20\ rev

total revolution of the washer is equal to 20 rev.

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Lera25 [3.4K]
The answer would be 45 km
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