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german
3 years ago
15

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

Step-by-step explanation:

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

A model shows a total of c cups divided into 10 sections, each labeled 2 and 1 fourth.

Part A

Which equation models the total number of cups of flour, c, Henry needs?

c+214=10

214×c=10

10+c=214

214×10=c

Part B

How many cups of flour does Henry need?

2014cups

2212cups

2434cups

2512cups

Part C

Estimate how much flour Henry would need to make 15 batches of cookies. Explain.

I would round 214 to 2, so Henry would need about 30 cups of flour.

I would round 214 to 3, so Henry would need about 45 cups of flour.

I would round 214 to 1, so Henry would need about 15 cups of flour.

I would round 214 to 234, so Henry would need about 30 cups of flour.​

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Weight = density*volume

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4 years ago
The sum of 25 and twice a number is 75. Find the number.
Sever21 [200]

Answer:

50

Step-by-step explanation:

25*2= 50+25= 75

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QRST is a square. PQ = 2√ RU = 4<br> What is the length of SU? Round to the nearest tenth.
777dan777 [17]

Answer:

SU=3.5\ units

Step-by-step explanation:

step 1

In the isosceles right triangle PQT

PQ=PT ----> because is an isosceles triangle

Applying the Pythagoras Theorem

we have

PQ=PT =\sqrt{2}\ units

QT^{2}=PQ^{2} +PT^{2}

substitute the values

QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}

QT^{2}=4

QT=2\ units

step 2

In the square QRST

RS=QT=2\ units

step 3

In the right triangle RSU

Applying the Pythagoras Theorem

RU^{2}=RS^{2} +SU^{2}

we have

RU=4\ units

RS=2\ units

substitute the values and solve for SU

4^{2}=2^{2} +SU^{2}

SU^{2}=4^{2}-2^{2}

SU^{2}=12

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3 years ago
On August 2nd, 1988, a US District Court judge imposed a fine on the city of Yonkers, New York, for defying a federal court orde
Minchanka [31]

Answer:

a)

A(t) = 1,000,000 + 10,000,000t

B(t)= 0.01 +0.02t

b) No.

Step-by-step explanation:

a)<u> Penalty A:</u> 1 million dollars on August 2 and the fine increases by 10 million dollars each day thereafter.

If t represents the number of days after August 2,

A(t) = 1,000,000 + 10,000,000t

<u>Penalty B</u>: 1 cent on August 2 and the fine doubles each day thereafter.

A(t) = 0.01 + 2t(0.01) = 0.01 + 0.02t

b) Assuming your formulas in part (a) hold for t≥0, is there a time such that the fines incurred under both penalties are equal?

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1,000,000 + 10,000,000t=0.01+0.02t\\9,999,999.98t=-999,999.99

By taking a look at this equation, we see that when we solve for t, t will be a negative number. Since the formulas are valid for t≥0, we can conclude that there won't be a time such that the fines are equal.

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