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2 years ago

Need help what is the answer

Mathematics

2 answers:

melomori [17]2 years ago

3 0

Answer:

76575755

Step-by-step explanation:

USPshnik [31]2 years ago

3 0

Answer is A

- The domain is what x values can exist on a curve, or graph; the y for range. In this case, the domain is restricted, given another condition, to essentially a list of x-values, namely -5, 0 and 1. Note that on the function you have mentioned can exist anywhere in x normally, and hence anywhere in y such that the relationship between the two holds, as it is one-to-one and has no discontinuities and asymptotes; basically anywhere x or y cannot exist, but is restricted as an extra condition. Going back to the one-to-one point; this means one x-value to one y-value, or every x has a unique y. So in this case, all we have to do is plug in the x-value into the function to find it’s unique y-value. That being 2, -2 and -2 and 4/5 going from left to right.

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Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.

Serga [27]

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ =90

LN = LN {Common}

∠MLN = ∠QLN {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180 {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

8 0

4 years ago

Point A has coordinates (-5, 3). If point (1,6) is

gtnhenbr [62]

Answer:

$(3, 7)$

Step-by-step explanation:

(4/3)P -(4/3)A + A = B . . . . . . add A

(4P -A)/3 = B . . . . . . . . . . . . . simplify

Then the coordinates of point B are ...

B = (4(1, 6) -(-5, 3))/3 = (9, 21)/3

B = (3, 7)

8 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,