What is the SLOPE of a line PERPENDICULAR to the Given equation y = 1/3x + 1
1 answer:
You might be interested in
Answer:
Option 4: <u>(2x + 16)° + (x)° = 180°</u>
Step-by-step explanation:
See the attached figure.
For a quadrilateral inscribed in a circle
The opposite angles are supplementary.
So, ∠D + ∠B = 180°
From the figure:
∠B = x° and ∠D = (2x+16)°
∴ <u>(2x + 16)° + (x)° = 180°</u>
