Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
Answer would be 3/5 (filler)
Answer:
Side CA = 7.8
Step-by-step explanation:
<u>Given:</u>
Acute angled 
.
AB = 10
BC = 12
We can use cosine rule here to find the side AC = b
<em>Formula for cosine rule:
</em>
Where
a is the side opposite to 
b is the side opposite to 
c is the side opposite to 
To the nearest tenth <em>b = 7.8</em>
Answer:
9/14
Step-by-step explanation:
3/8 * 3/7 * 4/1
~Multiply
9/56 * 4/1
~Multiply again
36/56
~Simplify
9/14
Best of Luck!
Answer:
0.8 percent
Step-by-step explanation:
In order to find the answer of .8 which is equivalent to 80%, you would have to do 48 divided by 60.
