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1 year ago

How many minutes are there from 19 to 7 until 17 past 7?

Mathematics

2 answers:

fredd [130]1 year ago

8 0

Answer:

Step-by-step explanation:

Naily [24]1 year ago

6 0

The answer for this question is 0

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PLEASE HELP 15 POINTS...PLEASE HELP

sasho [114]

Answer:

-4

Step-by-step explanation: it is intercepting the -4 so i think -4 is the right answer

8 0

3 years ago

Read 2 more answers

Is lmn congruent to opq if so name the postulate

insens350 [35]

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

Statements Reasons

1). LM ≅ OP 1). Given

2). MN ≅ PQ 2). Given

3). ∠P ≅ ∠M 3). Given

4). ΔLNM ≅ ΔOQP 4). By the SAS postulate of congruence.

[Side - Angle - Side]

Therefore, Option (A) will be the answer.

5 0

3 years ago

Without actually carrying out the steps of multiplication, determine whether the product of 15.1 and 0.9 will be larger or small

yan [13]

Answer: Smaller

Step-by-step explanation: The product of 15.1 and 0.9 will be smaller than 15.1. This is because 0.9 is smaller than 1 and since 15.1 * 1 is 15.1, we know that anything smaller than 1 will result in the product of it and 15.1 being smaller.

Would appreciate brainly <3

7 0

2 years ago

Read 2 more answers

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

Law Incorporation [45]

The probability that Jenny gets to choose lunch is 64% 0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

7/11 = 0.636 = 0.64 (rounded)

once again same answer

4 0

2 years ago