Answer:
T = 58 + 273.15 = 331.15
R = 0.082 atm
V = 250.0 mL / 1000 = 0.25 L
P = n x R x T / V
P = 2.48 x 0.082 x 331.15 / 0.25
P = 67.342 / 0.25
P = 269.368 atm
Explanation:
Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains
g of lithium
So, % lithium by mass in second sample =
% = 18.8%