It has 78 neutrons in a cesium
When waves bounce back after meeting a surface, it is called Reflection.
Answer : The value of
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
![ATP(aq)+H_2O(l)\rightarrow ADP(aq)+HPO_4^{2-}(aq)](https://tex.z-dn.net/?f=ATP%28aq%29%2BH_2O%28l%29%5Crightarrow%20ADP%28aq%29%2BHPO_4%5E%7B2-%7D%28aq%29)
The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
= 5.0 mM
= 0.60 mM
= 5.0 mM
Now put all the given values in this expression, we get
![Q=\frac{(0.60)\times (5.0)}{(5.0)}=0.60mM=0.60\times 10^{-3}M](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%280.60%29%5Ctimes%20%285.0%29%7D%7B%285.0%29%7D%3D0.60mM%3D0.60%5Ctimes%2010%5E%7B-3%7DM)
Now we have to calculate the value of
.
The formula used for
is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = ![8.314\times 10^{-3}kJ/mole.K](https://tex.z-dn.net/?f=8.314%5Ctimes%2010%5E%7B-3%7DkJ%2Fmole.K)
T = temperature = ![37.0^oC=273+37.0=310K](https://tex.z-dn.net/?f=37.0%5EoC%3D273%2B37.0%3D310K)
Q = reaction quotient = ![0.60\times 10^{-3}](https://tex.z-dn.net/?f=0.60%5Ctimes%2010%5E%7B-3%7D)
Now put all the given values in the above formula 1, we get:
![\Delta G_{rxn}=(-30.5kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (310K)\times \ln (0.60\times 10^{-3})](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%28-30.5kJ%2Fmol%29%2B%5B%288.314%5Ctimes%2010%5E%7B-3%7DkJ%2Fmole.K%29%5Ctimes%20%28310K%29%5Ctimes%20%5Cln%20%280.60%5Ctimes%2010%5E%7B-3%7D%29)
![\Delta G_{rxn}=-49.6kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D-49.6kJ%2Fmol)
Therefore, the value of
is -49.6 kJ/mol
<span>The copper will disengage from the sulfate and become evident in the aqueous solution, leading to greater uptake of sulfate by the metallic magnesium. This will lead to the creation of greater copper isolated.</span>