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rosijanka [135]
2 years ago
7

Chose the two factors that work together to create the global wind patterns that operate in the atmosphere.

Chemistry
1 answer:
grin007 [14]2 years ago
3 0
Global wind patterns are mainly determined by unequal heating of the earth's surface, changes in air pressure, and earth's rotation. Change in air pressure: Air mainly circulates due to change in air pressure. It moves from a region of high air pressure to the region of lower air pressure.
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a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0
3 years ago
Write the symbol for each of the following ions:
kap26 [50]

Answer:

a) _{31}^{71}\textrm {P^{3+}}

b) _{35}^{80}\textrm {Br^{-}}

c) _{90}^{232}\textrm {Th^{4+}}

d) _{38}^{87}\textrm {Sr^{2+}}

Explanation:

For neutral atoms:

Atomic Number (Z)= number of protons = number of electrons

Mass number (A) = number of protons + number of neutrons

For ions with positive net charge:

Number of protons = Z + net charge

For ions with negative net charge:

Number of protons= Z - net charge

a) A = 71, Charge = +3

Number of electrons = 28

Number of protons = 28 +3 =31

_{31}^{71}\textrm {P^{3+}}

b)  A = 35, Z = 45+35=80, Charge = -1

Number of protons =35

Number of neutrons = 45

Number of electrons = 36

Charge = Number of protons- Number of electrons =35-36 = -1

_{35}^{80}\textrm {Br^{-}}

c)  Charge = +4

Number of electrons = 86

Number of protons = Z = 86+4 = 90

mass number = A = 90+142 = 232

_{90}^{232}\textrm {Th^{4+}}

d)  Charge = +2

Atomic number = Number of protons = Z = 38

mass number = A = 87

_{38}^{87}\textrm {Sr^{2+}}

3 0
3 years ago
Which of the following options correctly ranks solid iodine, liquid bromine, and chlorine gas in order of increasing intermolecu
tatuchka [14]

Answer:

solid iodine chlorine gas

7 0
3 years ago
Pls help me. Show proof on why it’s that answer.
natulia [17]
The answer is “the sustainability of the ecosystem” because if the ecosystem isn’t sustainable enough for many different organisms to live in it then the biological diversity of the ecosystem will decrease.
6 0
3 years ago
Still using the reaction from the video, what is the limiting reagent when 2 moles of Al are reacted
kondaur [170]

The limiting reagent will be Al

<h3>What are limiting reagents?</h3>

They are reagents that limit the quantity of products that are formed in reactions.

From the equation of the reaction:

4Al + 3O_2 --- > 2Al_2O_3

The mole ratio of Al to O2 is 4:3.

With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.

With 2 moles of O2, the amount of Al required should be:

                          2 x 4/3 = 2.67 moles.

With 2 moles of Al, the amount of O2 required should be:

                    2 x 3/4 = 1.5 moles

Thus, O2 is in excess by 0.5 moles.

More on limiting reagents can be found here: brainly.com/question/11848702

#SPJ1

8 0
1 year ago
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