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rosijanka [135]
3 years ago
7

Chose the two factors that work together to create the global wind patterns that operate in the atmosphere.

Chemistry
1 answer:
grin007 [14]3 years ago
3 0
Global wind patterns are mainly determined by unequal heating of the earth's surface, changes in air pressure, and earth's rotation. Change in air pressure: Air mainly circulates due to change in air pressure. It moves from a region of high air pressure to the region of lower air pressure.
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Which statement describes the process of wind erosion?
alukav5142 [94]

Answer:

E

Explanation:

E

5 0
3 years ago
An isotope of potassium with a half-life of roughly one billion years is often used in radioactive dating. This isotope decays t
Archy [21]

Answer : The chemical symbol for the element that results from this process is, (Ar) for argon.

Explanation :

Electron capture : In this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. Simply, a proton and an electron combines together to form a neutron. Mass number does not change in this process.

_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}

The equation for the given reaction is,

_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}

Thus, the chemical symbol for the element that results from this process is, argon (Ar).

5 0
4 years ago
List down the types of intermolecular forces that exist between molecules (or basic units) in the species given below: (a) benze
slava [35]
(a) benzene (C6H6) - <span>nonpolar molecules . Only dispersion forces are present.
</span>
(b) CH3Cl -  <span>Chloroform ; polar molecules. Both dispersion and dipole-dipole forces are present.
</span>
(c) PF3 -  <span>Phosphorus triflouride ; has polar bonds but has nonpolar molecule due to its symmetrical structure. Only dispersion forces are present.
</span><span>
(d) NaCl - </span><span>Sodium chloride ; ionic compound. Both ion-ion and dispersion forces are present.</span><span>

(e) CS2 - </span><span>Carbon disulfide ; nonpolar molecules. Only dispersion forces are present.</span>
3 0
3 years ago
What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 3
grandymaker [24]

Mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current is 19.55 g

Given, I=8.70A, t=33.5min=33.5*60=2010 sec, m of Ag = 19600g M=107.87 g/mol

From  faradays law we can write q=I*t= 8.70*2010=17487 C.

moles of Ag =17487/ 19600=0.1812 moles

Ag deposited = 0.1812*107.87 = 19.55 g

<h3>Silver </h3>

Having the atomic number 47 and the Latin word argentum, which means "bright" or "white," silver is a chemical element. Its symbol is Ag. The highest electrical, thermal, and reflectivity of any metal are displayed by this transition metal, which is soft, white, and lustrous. The metal can be found in the Earth's crust in three different forms: as an alloy with other metals like gold and in minerals like argentite and chlorargyrite. It can also be found in its pure, free elemental form, also known as "native silver." During the refining of copper, gold, lead, and zinc, the majority of silver is created as a byproduct. As a valuable metal, silver has long been treasured.

What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g

Learn more about Silver here:

brainly.com/question/14587716

#SPJ4

4 0
2 years ago
Calculate the volume in cm^3 of 325.0 dg of alcohol. Alcohol has a density of 0.785g/mL.
Masteriza [31]
Answer:
106 mL

Explanation:
In order to be able to answer this question, you must understand what the density of a substance tells you.
The density of a substance is nothing more than the mass of that substance that occupies one unit of volume.
In your case, the density of ethanol is given in Grams per milliliter, which means that one unit of volume will be
1 mL
.
So, ethanol has a density of
0.785 g mL
−
1
, which is equivalent to saying that if you take exactly
1 mL
of ethanol and weigh it, you will end up with a mass of
0.785 g
.
Now, you know that the volume you're using has a mass of
83.3 g
. Well, if you get
0.785 g
for every
1 mL
of ethanol, it follows that this much mass will correspond to a volume of
83.3
g ethanol
⋅
ethanol's density

1 mL
0.785
g ethanol
=
106.11 mL
Rounded to three sig figs, the answer will be
V
ethanol
=
106 mL



Hope this helps
5 0
3 years ago
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