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BlackZzzverrR [31]
3 years ago
6

John and Alex were asked to make a 0.70 M solution. John measure out .35 L from the 2.0 M solution before asking how much soluti

on was needed. Alex remembered that measured out solutions are never put back in the stock bottle so went ahead and used all that was measured out. How many liters of the 0.70 M solution was made?
Chemistry
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

1.0 L

Explanation:

Given data

  • Initial volume (V₁): 0.35 L
  • Initial concentration (C₁): 2.0 M
  • Final volume (V₂): ?
  • Final concentration (C₂): 0.70 M

John and Alex prepared a diluted solution from a concentrated one. We can find the volume of the diluted solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₂ = C₁ × V₁ / C₂

V₂ = 2.0 M × 0.35 L / 0.70 M

V₂ = 1.0 L

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How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
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Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

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