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Aliun [14]
2 years ago
15

The reaction of nitrogen with methane in excess oxygen produces water, ________, and ___________. N2(g) + O2(g) + CH4(g) → CO2(g

) + H2O(g) + NO2(g) A) carbon oxide, nitrogen oxide B) carbon oxygen, nitrogen oxygen C) carbon dioxide, nitrogen dioxide D) dicarbon oxide, dinitrogen oxide
Chemistry
1 answer:
IrinaVladis [17]2 years ago
3 0

Answer:

C.

Explanation:

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1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
HZ is a weak acid. An aqueous solution of HZ is prepared by dissolving 0.020 mol of HZ in sufficient water to yield 1.0 L of sol
dlinn [17]

Answer: below is the calculation for Ka

Explanation:

Download pdf
7 0
2 years ago
On a balance, you have beakers of AgNO3AgNO3 solution and NaClNaCl solution. When mixed, they will form AgCl(s)AgCl(s). What wil
statuscvo [17]

Explanation:

According to the law of conservation of mass, mass can neither be created nor it can be destroyed. But it can be simply transformed from one form to another.

Therefore, when AgNO_{3} is added to NaCl then the compound formed will have same mass as that of reactants.

       AgNO_{3} + NaCl \rightarrow AgCl + NaNO_{3}

Total mass of reactants is (169.87 + 58.44) g/mol = 228.31 g/mol

Total mass of products is (143.32 + 84.99) g/mol = 228.31 g/mol

Thus, we can conclude that mass of the new mixture will stay the same.

6 0
3 years ago
What are the number of protons, neutrons, and electrons in an atom of Tellurium- 129?
deff fn [24]

Answer:

Number of protons = 52, Number of electrons = 52, Number of neutrons = 76

Explanation:

3 0
3 years ago
If a liquid substance is transferred to a different container, what can be predicted about the volume of the liquid in the new c
taurus [48]

The same

Explanation:

If a liquid substance is transferred to a different container, the volume of the liquid in the new container will remain the same.

The volumes of liquids are fixed and does not change. Wherever they are contained, just like solids, they maintain their constant space.

  • Volume is the amount of space occupied by a body.
  • Gases do not have fixed volume as they fill their containers and they take up the shape.
  • Solids and liquids have a fixed volume.
  • They do not change their volume.

learn more:

State of matter brainly.com/question/10972073

#learnwithBrainly

8 0
2 years ago
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