The calendar obviously has an integral number of years and months in 400 years. If it has an integral number of weeks, then it will repeat itself after that time. The rules of the calendar eliminate a leap year in 3 out of the four century years, so there are 97 leap years in 400 years. The number of excess days of the week in 400 years can be found by ...
(303·365) mod 7 + (97·366) mod 7 = (2·1 + 6·2) mod 7 = 14 mod 7 = 0
Thus, there are also an integral number of weeks in 400 years.
The first day of the week is the same at the start of every 400-year interval, so the calendar repeats every 400 years.
Given:
The function is:
To find:
The value of 
.
Solution:
We have,
Putting 
, we get
On combining like terms, we get
Therefore, the required function is .
Answer:
x = 25°
Step-by-step explanation:
3x + 2x + x + 30° = 180°
6x + 30° = 180°
6x = 150°
x =25°
=> 3x = 25 * 3 = 75°
=> 2x = 25 * 2 = 50°
=> x + 30° = 25° + 30° = 55°
Answer:
3 and 11
Step-by-step explanation:
Given 2 sides with third side x , then
difference of 2 sides < x < sum of 2 sides , that is
7 - 4 < x < 7 + 4
3 < x < 11
Thus the possible values the third side cannot be are 3 and 11
