The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 =
{-5, 3}
Answer:
2:55 P.M.
Step-by-step explanation:
First, add the amount of time Jim played outside; 45+55=100
100 minutes is equal to 1 hour 40 minutes.
If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.
Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.
To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.
Hope this helped !!!
The length of DE is 39 and the length of EF is 36 because we can see from side AC and DF that triangle DEF is just triangle ABC dilated by 3.
Answer:
it will take 1.4 hours for the two trains to be 294 miles apart
Step-by-step explanation:
Let t be the time taken for each train
The westbound train travels at 95 miles per hour.
Speed of westbound train = 95
time = t
Distance = speed * time = 95 t
The eastbound train travels at 115 miles per hour
Speed of eastbound train = 115
time = t
Distance = speed * time = 115 t
both trains are 294 miles apart means the distance between both trains are 294 miles
So we add the distance of both trains and set it equal to 294
95t + 115t = 294
210 t =294
t = 1.4
So, it will take 1.4 hours for the two trains to be 294 miles apart
I think the answer is 0.541 I am not sure
