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notka56 [123]
3 years ago
15

Dillon studied 3 6/7 hours for his English test. He studied 5 3/14 hours for his math test. How much longer did he study for his

math test? (Simplify the answer and write it as a mixed number.)
Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

1 \frac{5}{14}, \frac{19}{14}

Step-by-step explanation:

How much longer did he study for his math test?

E=3\frac{6}{7}

M=5\frac{3}{14}

x=difference

An equation for this would resemble this:

M- E=x

Now before we get into any equation solving let's get the <em>denominators </em>equal to each other. we can do this by <em>multiplying </em>the <em><u>numerator</u></em> and <u><em>denominator</em></u><em> </em>by 2.     \frac{6(2)}{7(2)}=\frac{12}{14}

Now we can solve the equation:

5\frac{3}{14} - 3\frac{12}{14} =\frac{19}{14}

1 \frac{5}{14}, as a mixed number

<em>plz mark me brainliest. :0</em>

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To visit her grandmother, Melek takes a motorcycle 3.8 kilometers and a horse 3.32 kilometers. In total, the journey takes 50.54
lbvjy [14]

Answer:

Therefore, total number of Kilometers Melek covered =3.3 + 3.32 = 6.62 kilometers.

Step-by-step explanation:

Distance covered by motorcycle = 3.8 kilometers.

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Total time taken to complete the journey = 50.54 minutes.

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8 0
3 years ago
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Sergio [31]
(8*6)-3 is your answer 
4 0
4 years ago
I really need help with this last problem
gogolik [260]

Answer:


Step-by-step explanation:

a. Profit, p, earned from selling x hats when hat will be sold for $12 each:

p = 12x


b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:

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x >= 1500/12 = 12.5

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3 0
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Use the given endpoint R and midpoint M of line RS to find the coordinates of the other endpoins.
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6 0
3 years ago
when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0
2 years ago
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