Answer:
Therefore, total number of Kilometers Melek covered =3.3 + 3.32 = 6.62 kilometers.
Step-by-step explanation:
Distance covered by motorcycle = 3.8 kilometers.
Distance covered by horse = 3.32 kilometers.
Total time taken to complete the journey = 50.54 minutes.
We need to find the total number of kilometers Melek took the journey.
We are given time. But we need not to do anything with given time.
We just need to add the journey took by motorcycle and journey took by horse.
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Answer:
Step-by-step explanation:
a. Profit, p, earned from selling x hats when hat will be sold for $12 each:
p = 12x
b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:
p = 12x >= 1500
x >= 1500/12 = 12.5
So the minimum number of hats that must be sold = 13
c. New hat price = $15 so p = 15x
p = 15x >= 1500
x >= 1500/15 = 10
So the new minimum = 10 which is 3 fewer.
S(-6, 4)
If you plot on a simple graph you will find the other end point S there
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.