Answer:
(you have to have the .0 since it says to round to the nearest <em>tenth</em>)
Step-by-step explanation:
The formula for the surface area of a rectangular prism is:
So just plug in the values.
Height= 4
Width=2
Length=5
Answer:D
Step-by-step explanation:
(3x^3 - 5x^2 + 4x - 9)-(7x^3 - 8x^2 - 5x + 10)
open brackets
3x^3 - 5x^2 + 4x - 9 - 7x^3 + 8x^2 +5x - 10
Collect like terms
3x^3-7x^3-5x^2+8x^2+4x+5x-9-10
-4x^3+3x^2+9x-19
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
1) given
2) definition of an angle bisector
3) reflexive
4) 
(ASA)
5) 
(CPCTC)
